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Answer:
∠CAB = 28°
∠DAC = 64°
Step-by-step explanation:
What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.
<u>Left</u>
Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...
x + x + ∠AEB = 180°
2x = 180° -124° = 56°
x = 28°
The measure of angle CAB is 28°.
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<u>Right</u>
Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.
∠BCA = ∠DAC = 64°
The measure of angle DAC is 64°.
(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)
C would be the right answer just done the test
Answer:
x(t) = - 5 + 6t and y(t) = 3 - 9t
Step-by-step explanation:
We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).
Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.
x(t) = - 5 + t and y(t) = 3 - 6t and
x(t) = - 5 + 6t and y(t) = 3 - 9t
Both of the above sets of equations satisfy this above conditions.
Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.
So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t satisfies this condition.
Therefore, this is the answer. (Answer)
