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bija089 [108]
3 years ago
13

√45 is the distance between which of the following complex numbers?

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Step-by-step explanation:

we don't see the complex numbers.

so, we cannot check their distances.

a suspicion, though.

sqrt(45) a distance between 2 complex numbers is

sqrt(a² + b²).

so,

a² + b² = 45

a nice combination of whole square numbers would be 6 and 3.

6² + 3² = 36 + 9 = 45

if that is the case, then that would mean one of the following committed numbers

6 + 3i

3 + 6i

-6 + 3i

6 - 3i

-6 - 3i

-3 + 6i

3 - 6i

-3 - 6i

one of these numbers must be the result of the subtraction of the 2 provided complex numbers.

remember

(a + bi) - (c + di) = a-c + (b-d)i

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Cylinder and 6 units

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find the volume of the cylinder with the same radius and double the height when the radius is 5 and the height is 2​
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Answer:

100pi

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8 0
2 years ago
Vanessa deposits $24,000 into each of two savings accounts. Account I earns 2. 4% interest compounded annually. Account II earns
ikadub [295]

The sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)

<h3>How to calculate compound interest's amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% per unit time, and it is left for T unit of time for that compound interest, then the interest amount earned is given by:

CI = P(1 +\dfrac{R}{100})^T - P

The final amount becomes:

A = CI + P\\A = P(1 +\dfrac{R}{100})^T

<h3>How to calculate simple interest amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

I = \dfrac{P \times R \times T}{100}

For the considered case, we're given that:

  • Initial amount in both accounts deposited = $24,000 = P
  • Type of interest: Compound interest in first account and simple interest in second account
  • Unit of time: Annually
  • Rate of interest = 2.4% annually = R
  • Total unit of time for which amount is to be calculated: 5 years = T

In first account, the final amount at the end of 5 years is evaluated as:

A = 24000(1 + \dfrac{2.4}{100})^4 = 24000(1.024)^4  \approx 27021.59\: \rm (in \:  dollars)

In second account,  the final amount at the end of 5 years is evaluated as:

A = 24000 +  \dfrac{24000 \times 2.4 \times 5}{100} = 24000 + 2880 = 26880 \text{\: (in dollars)}

Total amount after 5 years in these accounts = 27021.59 + 26880 = 53901.59 (in dollars)

Thus, the sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)

Learn more about compound interest here:

brainly.com/question/11897800

4 0
2 years ago
Find a vector of magnitude 3 in the direction of v = 10i - 24k. The vector is Oi-Oj+k (Simplify your answer. Use integers or fra
Soloha48 [4]

Given :

A vector v = 10i - 24k.

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A vector of magnitude 3 in the direction of v = 10i - 24k.

Solution :

Unit vector in the direction  of vector v is :

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Now , vector of magnitude 3 in direction v is :

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Can someone complete the square??
ira [324]

THE ANSWER IS..... X1= -6 & X2=0

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