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bija089 [108]
3 years ago
13

√45 is the distance between which of the following complex numbers?

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Step-by-step explanation:

we don't see the complex numbers.

so, we cannot check their distances.

a suspicion, though.

sqrt(45) a distance between 2 complex numbers is

sqrt(a² + b²).

so,

a² + b² = 45

a nice combination of whole square numbers would be 6 and 3.

6² + 3² = 36 + 9 = 45

if that is the case, then that would mean one of the following committed numbers

6 + 3i

3 + 6i

-6 + 3i

6 - 3i

-6 - 3i

-3 + 6i

3 - 6i

-3 - 6i

one of these numbers must be the result of the subtraction of the 2 provided complex numbers.

remember

(a + bi) - (c + di) = a-c + (b-d)i

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one number is twice another number. if the 12 is subtracted from the larger number the result is 7 more than the smaller number.
solniwko [45]

Answer:

Step-by-step explanation:

3 0
3 years ago
Kareem wrote the values shown below.
grandymaker [24]

Answer:

Option D is correct.

\lfloor 4.8 \rfloor  and \lceil 3.2 \rceil

Step-by-step explanation:

Floor function states that the greatest integer that is less than or equal to x.

It is represented by: \lfloor x \rfloor

Ceiling function states that the least integer that is greater than or equal to x.

It is represented by: \lceil x \rceil

As per the statement:-

Kareem wrote the values show below:

\lceil 3.2 \rceil,  \lfloor 2.7 \rfloor,  \lceil 2.9 \rceil and \lfloor 4.8 \rfloor.

by definition:

\lceil 3.2 \rceil = 4

\lfloor 2.7 \rfloor = 2

\lceil 2.9 \rceil=3

\lfloor 4.8 \rfloor = 4

From the given options only pair which is equivalent is:

\lfloor 4.8 \rfloor  and \lceil 3.2 \rceil

7 0
2 years ago
What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis
Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)  

Step-by-step explanation:

\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

4 0
3 years ago
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The midpoint of mn is point p at (-4,6). If point m is at (8,-2), what are the coordinates of point n?
VashaNatasha [74]
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<u>
x + 8</u>                                 <u>y + -2</u><u>
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<u>multiply both sides by 2.

</u>x+8=-8                             y - 2 = 12
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</u>
Final Answer: (-16, 14)



7 0
3 years ago
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