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bija089 [108]
3 years ago
13

√45 is the distance between which of the following complex numbers?

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Step-by-step explanation:

we don't see the complex numbers.

so, we cannot check their distances.

a suspicion, though.

sqrt(45) a distance between 2 complex numbers is

sqrt(a² + b²).

so,

a² + b² = 45

a nice combination of whole square numbers would be 6 and 3.

6² + 3² = 36 + 9 = 45

if that is the case, then that would mean one of the following committed numbers

6 + 3i

3 + 6i

-6 + 3i

6 - 3i

-6 - 3i

-3 + 6i

3 - 6i

-3 - 6i

one of these numbers must be the result of the subtraction of the 2 provided complex numbers.

remember

(a + bi) - (c + di) = a-c + (b-d)i

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What is x in the equation 753.6=(3.14)(6)^2(x)
vichka [17]

Answer:

 x = 20/3 = 6.667

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "3.14" was replaced by "(314/100)". 2 more similar replacement(s)

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

          (7536/10)-(((314/100))*(6)^2*(x))=0

Step by step solution :

Step  1  :

1.1     6 = 2•3

(6)2 = (2•3)2 = 22 • 32

Equation at the end of step  1  :

 7536      314

 ———— -  ((——— • (22•32)) • x)  = 0

  10       100

Step  2  :

           157

Simplify   ———

           50

Equation at the end of step  2  :

 7536      157

 ———— -  ((——— • (22•32)) • x)  = 0

  10       50

Step  3  :

Dividing exponents :

3.1    22   divided by   21   = 2(2 - 1) = 21 = 2

Equation at the end of step  3  :

 7536     2826

 ———— -  (———— • x)  = 0

  10       25

Step  4  :

           3768

Simplify   ————

            5  

Equation at the end of step  4  :

 3768    2826x

 ———— -  —————  = 0

  5       25  

Step  5  :

Calculating the Least Common Multiple :

5.1    Find the Least Common Multiple

     The left denominator is :       5

     The right denominator is :       25

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

5 1 2 2

Product of all

Prime Factors  5 25 25

     Least Common Multiple:

     25

Calculating Multipliers :

5.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

5.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3768 • 5

  ——————————————————  =   ————————

        L.C.M                25  

  R. Mult. • R. Num.      2826x

  ——————————————————  =   —————

        L.C.M              25  

Adding fractions that have a common denominator :

5.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3768 • 5 - (2826x)     18840 - 2826x

——————————————————  =  —————————————

        25                  25      

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  18840 - 2826x  =   -942 • (3x - 20)

Equation at the end of step  6  :

 -942 • (3x - 20)

 ————————————————  = 0

        25      

Step  7  :

When a fraction equals zero :

7.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -942•(3x-20)

 ———————————— • 25 = 0 • 25

      25    

Now, on the left hand side, the  25  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -942  •  (3x-20)  = 0

Equations which are never true :

7.2      Solve :    -942   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

7.3      Solve  :    3x-20 = 0

Add  20  to both sides of the equation :

                     3x = 20

Divide both sides of the equation by 3:

                    x = 20/3 = 6.667

One solution was found :

                  x = 20/3 = 6.667

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Step-by-step explanation:

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Aneli [31]

Answer:

is it this way

j=92

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Two sides of a triangle are exactly the Same length. The length of the third side is four cm shorter than the two equal sides. F
liubo4ka [24]

Answer:

15 cm, 15 cm, 11 cm

Step-by-step explanation:

let the equal sides be x then the third side is x - 4

The perimeter is the sum of the 3 sides and is 41 cm , then

x + x + x - 4 = 41

3x - 4 = 41 ( add 4 to both sides )

3x = 45 ( divide both sides by 3 )

x = 15

x - 4 = 15 - 4 = 11

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