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bija089 [108]
3 years ago
13

√45 is the distance between which of the following complex numbers?

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Step-by-step explanation:

we don't see the complex numbers.

so, we cannot check their distances.

a suspicion, though.

sqrt(45) a distance between 2 complex numbers is

sqrt(a² + b²).

so,

a² + b² = 45

a nice combination of whole square numbers would be 6 and 3.

6² + 3² = 36 + 9 = 45

if that is the case, then that would mean one of the following committed numbers

6 + 3i

3 + 6i

-6 + 3i

6 - 3i

-6 - 3i

-3 + 6i

3 - 6i

-3 - 6i

one of these numbers must be the result of the subtraction of the 2 provided complex numbers.

remember

(a + bi) - (c + di) = a-c + (b-d)i

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VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV this is middle school math
Yuri [45]

Answer:

first method

<u>2</u><u>2</u>=<u>5</u>

7. x

we cross multiply to get

<u>2</u><u>2</u><u>x</u>= <u>5</u><u>×</u><u>7</u>

22. 22.

x= <u>3</u><u>5</u>

22

=1.59

second method

<u>2</u><u>2</u>=<u>5</u>

7. x

we multiply the denominators to get 7x

then we multiply each term by 7x

7x×<u>2</u><u>2</u> = <u>5</u>×7x

7. x

here the 7 and 7 will cancel out and the x and x will cancel out to get

<u>2</u><u>2</u><u>x</u>= <u>3</u><u>5</u>

22. 22

= 1.59

5 0
3 years ago
9. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of
netineya [11]

Answer:

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 12, \sigma = 3

What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?

This is 1 subtracted by the pvalue of Z when X = 16. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 12}{3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

1 - 0.9082 = 0.0918

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

5 0
3 years ago
Find the value of the expression if x=-7
LUCKY_DIMON [66]

Answer: -16

Step-by-step explanation:

49 would be the result of -7 squared. Due to the fact it is negative, it would cancel out to be positive.

For the numerator, 49-1 is equivalent to 48.

48/x+4

-7+4 = -3

48/-3

= -16

5 0
3 years ago
Divisibility rules for 2, 5, and 10
Simora [160]

Answer:

none of these

Step-by-step explanation:

A number is divisible by 10 if the last digit of the number is 0. The numbers 20, 40, 50, 170, and 990 are all divisible by 10 because their last digit is zero, 0.

5 0
3 years ago
What is the volume of a hemisphere with a radius of 26.7 m, rounded to the nearest tenth of a cubic meter?
attashe74 [19]

Answer:

39,865.1m^3

Step-by-step explanation:

a hemisphere is half a sphere.

And if the formula for the volume of a sphere is:

V=\frac{4\pi r^3}{3}

we must calculate the volume of the sphere and in the end divide by two to find the volume of the hemisphere.

Since the radius is:

r=26.7m

substituting this into the formula for volume:

V=\frac{4\pi (26.7m)^3}{3} \\\\V=\frac{4(3.1416)(19,034.163m^3)}{3} \\\\V=79,730.12m^3

this is the volume of the total sphere, thus the volume of a hemisphere is:

\frac{V}{2}=\frac{79,730.12m^3}{2}\\  =39,865.06m^3

rounding to the nearest tenth:

39,865.1m^3

8 0
3 years ago
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