Here is the answer all you have to do is go 1984 divide by 42 47.23809524
Answer:
1: 11√3 - 7√6
2: 11√3 - 7√6
3: -9
4:12
Step-by-step explanation:
To add radicals they need to have the same radical part for the first one we have
7√3- 4√6 + √48 - √54
We can simplify the last two into 4√3 and 3√6
So we have 7√3 - 4√6 + 4√3 - 3√6
adding similar radicals we get
11√3 - 7√6
For the second one we have 11√3 - 7√6
There's nothing we can do from here so keep that as your answer
This one is quite easy -3√9
square root of 9 is 3
so we have -3*3 which is -9
next is
4√9
same deal as the one before
3*4=12
Answer:
6°F
58°F
Step-by-step explanation:
From the data Given :
Temperature rise in Buffalo by noon time = 14°F
The initial temperature at Buffalo = - 8°F
Rise in temperature = 14°F
Therefore, temperature at noon = (-8 + 14)°F = 6°F
B.)
Temperature at 6am in St. Louis = 32°F
Temperature at 6am in Juneau = - 26°F
Temperature difference :
(32 - (-26))°F
32 + 26
= 58°F
Temperature in St. Louis is 58°F higher
X is 7 and y is 2 I am pretty sure
Answer:
Step-by-step explanation:
Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42
Let X be the no of passengers who report
X is N(132, 42)
Or Z is 
a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.
the probability that the demand will exceed the capacity of this airplane
=

b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers
=
=0.4474+0.3907
=0.8381
c) the probability that the demand for this flight will be less than 100 passengers

d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers
=
e) 79th percentile of this distribution
=