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2 years ago

Make l the subject of formula when a=lb

Mathematics

1 answer:

mixas84 [53]2 years ago

6 0

Answer:

l = $\frac{a}{b}$

Step-by-step explanation:

a = lb ( isolate l by dividing both sides by b )

$\frac{a}{b}$ = l

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Find the missing leg of a triangle with legs of 7 and a hypotenuse of 10<br> Help please

ahrayia [7]

Answer:

i believe its 24 in for the other leg

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A farmer has some hens and goats. He counts a total of 60 eyes and 86 feet between them. How many hens does he have?.

ra1l [238]

The farmer has 17 hens.

<h3>What is a linear equation in two variables ?</h3>

An equation is linear if has highest degree of 1 and it has two variables.Generally they are in x and y.

For example -: 2x + 3y = 10

According to the given question a farmer has some hens and goats. He counts a total of 60 eyes and 86 feet between them.

Let us denote Hens by H and Goats by G.

We know both of them has 2 eyes each and we also know that a Hen has 2 legs and a Goat has 4 legs.

There fore the given data we can form two equations.

2H + 2G = 60 and 2H + 4G = 86.

Solving these two equations we have G = 13 and H = 17.

learn more more about linear equation in two variables here :

brainly.com/question/24085666

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3 0

2 years ago

Frankie solved the math problem below. Find the error in Frankie's work and explain it in words, using math language. 2 1/3 - 1

HACTEHA [7]

Given:

The expression is

$2\dfrac{1}{3}-1\dfrac{2}{5}$

To find:

The error in Frankie's work.

Solution:

We need to simplify $2\dfrac{1}{3}-1\dfrac{2}{5}$ , so

$2\dfrac{1}{3}=2\dfrac{1}{3}\times \dfrac{5}{5}$

$2\dfrac{1}{3}=2\dfrac{5}{15}$

and,

$1\dfrac{2}{5}=-1\dfrac{2}{5}\times \dfrac{3}{3}$

$1\dfrac{2}{5}=-1\dfrac{6}{15}$

Now,

$2\dfrac{1}{3}-1\dfrac{2}{5}=2\dfrac{5}{15}-1\dfrac{6}{15}$

$2\dfrac{1}{3}-1\dfrac{2}{5}=(2+\dfrac{5}{15})-(1+\dfrac{6}{15})$

$2\dfrac{1}{3}-1\dfrac{2}{5}=2+\dfrac{5}{15}-1-\dfrac{6}{15}$

$2\dfrac{1}{3}-1\dfrac{2}{5}=1-\dfrac{1}{15}$

$2\dfrac{1}{3}-1\dfrac{2}{5}=\dfrac{14}{15}$

Therefore, there is error in Frankie's last step. In that step, he did not subtract the mixed fraction correctly.

8 0

3 years ago

When evaluating (3.25 times 10 Superscript 5 Baseline) (1.82 times 10 Superscript 3 Baseline), what will be the exponent of 10 i

boyakko [2]

Answer:

The exponent of 10 in the product is 8.

Step-by-step explanation:

The expression is as follows:

$(3.25\times 10^{5})\cdot (1.82\times 10^{3})$

Exponent rule:

$a^{m}\times a^{n}=a^{m+n}$

Simplify the expression as follows:

$(3.25\times 10^{5})\cdot (1.82\times 10^{3})=3.25\times 10^{5}\times 1.82\times 10^{3}$

$=(3.25\times 1.82)\times (10^{5}\times 10^{3})\\\\=5.915\times 10^{5+3}\\\\=5.915\times 10^{8}$

Thus, the exponent of 10 in the product is 8.

3 0

3 years ago

Read 2 more answers

Α' β

yulyashka [42]

Answer:

8x² +36x -27=0

Step-by-step explanation:

2x²= 6x +3

Let's rewrite the equation into the form of ax²+bx+c= 0.

2x² -6x -3=0

Thus, a= 2

b= -6

c= -3

Sum of roots= $- \frac{b}{a}$

Since your roots are p and q, sum of roots= p +q

p +q= $- (\frac{ - 6}{2} )$

p +q= 6 ÷2

p +q= 3

Product of roots= $\frac{c}{a}$

pq= $- \frac{3}{2}$

<u>Quadratic equations</u><u>:</u>

x² -(sum of roots)x +(product of roots)= 0

Thus, we have to find the sum and the product of the new roots, p²q and pq².

p +q= 3

pq= -3/2

Product of new roots

= (p²q)(pq²)

= p³q³

= (pq)³

$= ( - \frac{3}{2} )^{3} \\ = - \frac{27}{8}$

sum of new roots

= p²q +pq²

= pq(p +q)

= (-3/2)(3)

= -9/2

Thus, the quadratic equation with roots p²q and pq² is

x² -(-9/2)x -27/8 = 0

$x ^{2} + \frac{9}{2} x - \frac{27}{8} = 0$

Multiply by 8 throughout:

$8 {x}^{2} + 36x - 27 = 0$

3 0

3 years ago