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2 years ago

Make l the subject of formula when a=lb

Mathematics

1 answer:

mixas84 [53]2 years ago

6 0

Answer:

l = $\frac{a}{b}$

Step-by-step explanation:

a = lb ( isolate l by dividing both sides by b )

$\frac{a}{b}$ = l

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In the diagram below segment DEF is shown (since all three letters are shown, they are collinear). If

monitta

Answer:

x = 4

Step-by-step explanation:

Given

DE = 3x + 2, EF = x + 5, DF = 23

As per segment addition postulate

DE + EF = DF

Substituting values:

3x + 2 + x + 5 = 23
4x + 7 = 23
4x = 16
x = 4

3 0

3 years ago

Find an equivalent fractions for each given fraction 200/100

balandron [24]

Answer:

2/1 or 400/200

Step-by-step explanation:

6 0

3 years ago

D/3+10=14 solve the equation

Tamiku [17]

Answer: d = 12

Step-by-step explanation: First isolate d/3 by subtracting 10 from both sides of the equation. That gives you d/3 = 4.

From here, since d is being divided by 5, multiply both sides of the equation by 5 so d = 12.

6 0

3 years ago

Godwin starts working on a job and works on it for 12 days and completes 40% of the

vagabundo [1.1K]

Answer:

100

Step-by-step explanation:

6 0

3 years ago

In the diagram, point D divides line segment AB in the ratio of 5:3. If line segment AC is vertical and line segment CD is horiz

Llana [10]

Answer:

$Point\ C = (2,-1)$

Step-by-step explanation:

Given

$A = (2,-6)$

$B = (10,2)$

$m:n = 5:3$

Required

Determine the coordinates of C

Since, point D divides line AB in ratio, 5 : 3;

We start by calculating the coordinates of D;

This is done as follows;

$D(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})$

Where

$(x_1,y_1) = (2,6)$

$(x_2,y_2) = (10,2)$

$m:n = 5:3$

$D(x,y) = (\frac{5 * 10 + 3 * 2}{5+3},\frac{5 * 2 + 3 * -6}{5+3})$

$D(x,y) = (\frac{50 + 6}{8},\frac{10 - 18}{8})$

$D(x,y) = (\frac{56}{8},\frac{-8}{8})$

$D(x,y) = (7},-1)$

Since AC is vertical

Then, Point C has the same x coordinate as A

$x-coordinate = 2$

Similarly;

Since CD is horizontal

Then, Point C has the same y coordinate as D

$y-coordinate = -1$

Hence,

$Point\ C = (2,-1)$

3 0

3 years ago