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wlad13 [49]
3 years ago
10

Write an equation in slope-intercept form for the line passing through the pair of points.

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0
First find your slope! by doing
y2-y1/x2-x1
in this case it would be
2-(-3)/-1-(-6)
It would give you 5/5 which would reduce to 1 meaning your slope equals 1
with your slope now you should use the point slope formula y-y1=m(x-x1)

i’m going to use the point (-1,2) so the equation would be

y-2=1(x-(-1))

simplifying that you would get

y-2=1x+1

then put it in y=mx+b form and get

y=x+3
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What is the measure of Angle R?
Ivanshal [37]

The sum of angles in triangle is equal to 180 degrees, so

<R =180-56-30

<R=94

8 0
3 years ago
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-2j &lt; -14
Novay_Z [31]

Step-by-step explanation:

-2j < -14

Divide both sides by -2:

j > 7. (D)

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Find the area of a rhombus with side length 6 and an interior angle with measure $120^\circ$.
Serhud [2]

Answer:

The area of a rhombus is 18\sqrt{3} square units.

Step-by-step explanation:

Side length of rhombus = 6 units.

Interior angle of rhombus = 120°

another Interior angle of rhombus = 180°-120° = 60°.

Draw an altitude.

In a right angled triangle

\sin \theta=\frac{opposite}{hypotenuse}

\sin (60)=\frac{h}{6}

\frac{\sqrt{3}}{2}=\frac{h}{6}

Multiply both sides by 6.

3\sqrt{3}=h

The height of the rhombus is 3\sqrt{3}.

Area of a rhombus is

Area=base\times height

Area=6\times 3\sqrt{3}

Area=18\sqrt{3}

Therefore, the area of a rhombus is 18\sqrt{3} square units.

8 0
2 years ago
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A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If
inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

(5+x)(10+x)=84

solve for x

Apply distributive property

50+ 5x+10x+x^2=84\\x^2+15x-34=0

solve the quadratic c equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+15x-34=0  

so

a=1\\b=15\\c=-34

substitute in the formula

x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}

x=\frac{-15\pm\sqrt{361}} {2}

x=\frac{-15\pm19} {2}

x=\frac{-15\pm19} {2}=2

x=\frac{-15\pm19} {2}=-17

therefore

The solution is x=2 ft

8 0
3 years ago
Hey! i’ll give brainliest help thanks
Natalka [10]

Answer:

its A

Step-by-step explanation:

4 0
3 years ago
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