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maxonik [38]
3 years ago
13

The value of 3(2f+3) when f= 5

Mathematics
2 answers:
kolbaska11 [484]3 years ago
5 0

Answer:

39

Step-by-step explanation:

First since f=5 , you should get rid of the f

2 * 5 = 10

so now the equation is 3(10+3)

Then you add the numbers in the parentheses

10 + 3 = 13

Then multiply it by 3

3 * 13 = 39

39 is your answer

PtichkaEL [24]3 years ago
4 0

Answer:

39

Step-by-step explanation:

2x5=10

10+3=13

13x3=39

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Answer: 1) AC = 13

The formua does not actually apply to all of the problems.

Step-by-step explanation:

1) The absolute value of -8 is added to the absolute value of 5. 8+5=13

2) Subtract the length of the EF from EG to get the length of FG 21 -6 = 15

3) Take what's given and create an equation to solve. 4x + 15 +39 =110. 4x = 110 - (15+39).

4x =110-54. 4x =56. x=56/4. x=14

4) Create another equation. You have two segments that add up to the length of EG, given =23

EF+FG=EG

(2x-12)+(3x-15)=23

5x - 27 = 23

5x= 23+27 5x =50. x = 10

Substitute 10 for x

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FG=3(10)-15. FG=15

EF+FG =EG.

8 + 15 = 23

5) 2/5 of 25 is 10 So EF is 10. Subtract from 25 to get FG

FG = 15

I hope this helps you.

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I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

5 0
3 years ago
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