Question

A triangle has vertices at A(-2,3), B(2,-2), and C(-2,-2). What is the area of the triangle?

Answer 1

Answer:

The area of the given triangle ABC is 10 units.

Step-by-step explanation:

we have the area of the triangle when points are given is given by the relation

Area of triangle=

$\frac{1}{2} {x1 \times (y2 - y3) + x2 \times (y3 - y1) + x3 \times (y1 - y2)}$

and hence putting the Value

triangle = 1/2*( -2*(-2+2)+2*(-2-3)+(-2)*(3+2))

= 1/2*(0+2*(-5)+(-2)*5)

= 1/2*(-10-10)

= 1/2*(-20)

= (-10) units

Since area of the triangle is always positive, we neglect the minus sign and take 10 units as its area.