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mrs_skeptik [129]
3 years ago
9

What are the factors of xsquared+4x+3

Mathematics
2 answers:
eduard3 years ago
5 0
What 2 numbers multiply to get 3 and add to get 4?
3 and 1
so
(x+3)(x+1) Is the factored form
Maslowich3 years ago
4 0
The answer would be (x+1)(x+3)
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What is a one-to-one function?
umka2103 [35]

Answer:

C.

Step-by-step explanation:

A one to one function is a function in which an element in a domain is corresponding to the a single element in the range. That is, each element in the domain has exactly one image in the range.

To answer the question that say : What is a one-to-one function?

A function f is called a one-to-one function if it never takes on the same value twice.

Therefore the correct answer is option C.

6 0
3 years ago
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Elina [12.6K]
Function A is linear

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6 0
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Which counting rule would you use to determine total seating arrangements for a group of 8 people at a table with 6 chairs? Sele
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5 0
3 years ago
30+5y_>4x I need the answer ASAP
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30+5y_>4x
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5 0
3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
2 years ago
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