Answer:
1.20
Step-by-step explanation:
Because .2 is in the tenths place and 0 is the hundredths so you round the hundredths to the tenths and since its 0 then it stays the same.
Answer: -630
Step-by-step explanation:
Given the nth term of a sequence;
a(n)=a(n−1)⋅(−9) and the first term of the sequence a(1) as 35, the third term of the sequence can be gotten by using the formula at when n = 3
If n = 3 and a(1) = 35;
a(3) = 35(3-1)•(-9)
a(3) = 35×2×-9
a(3) = 70×-9
a(3) = -630
There the 3rd term of the series will give us -630 according to the nth term of the formula given.
Answer:
True, False, False, False
Step-by-step explanation:
I'll find the lengths of all sides of the drawing before answering individual answers so that it's less confusing.
1) The question says that QR is a perpendicular bisector of TS. This means that the length of TQ and QS is the same. Also, since both triangles TRQ and SRQ share the same side RQ, and the angle between the two segments is 90 degrees, the two triangles are congruent (RTQ and RSQ) using SAS.
2) Side RT and TS will have the same length since the two triangles are congruent. (2x+1) = (4x-3) --> -2x = -4 --> x = 2. We can conclude that x = 2.
3) Now that we know that x = 2, we can find the length of side RS by replacing the x with 2. 4(2)-3 is 5, so RS = 5.
4) We can use the Pythagorean theorem to find RQ (Hypotenuse^2 = Other two sides added after being squared individually). Since the hypotenuse of triangle RSQ is RS which is 5, and one side is 4, we can input those into our equation. (5)^2 = (4)^2 + (RQ)^2. --> 25 = 16 + (RQ)^2 --> 9 = (RQ)^2 --> RQ = 3.
5) Since the two triangles RTQ and RSQ are congruent, side TQ and SQ also have the same length, since CPCTC (Corresponding parts of congruent triangles are congruent). QS is 4, so TQ will also be 4. This means that ST will be 8 (4+4). ST = 8
Now that we have all the clues, all we need to do is choose True or False.
RS = 5 is TRUE
RS = 4 is FALSE
ST = 10 is FALSE
QR = 4 is FALSE
Answer:
- N more than 4.
- 4 plus n.
-4 added with n.
Are some types of verbal expression for this expression.