Answer:
-38.2
Step-by-step explanation:
A^2 + 31 = 155 - I squared each of b and c for those numbers
a^2 = 155 - 31
a^2 = 124
a = 4 * sqrt(31)
Answer:
I think the answer is b ill look into it a Lil more
A) What is the mean of : 18, 22, 14, 30, 26
x = (18 +22+ 14+ 30+ 26)/5 = 22
(b) What is the sum of the squares of the differences between each data value and the
mean: (data point - x)² or (data point - 22)²
(18-22)² = 16
(22-22)² = 0
(14-22)² = 64
(30-22)² = 64
(26-22)² = 16
Sum = 16+0+64+64+16 = 160
(c) What is the standard deviation
s = √[(∑(x-22)²/(n-1)], where x is the data point, 20 the mean and n =5
√[(∑(x-22)² = 160 and n = 5 (5 data points) then s = 160(5-1) = 160/4 = 40
d) 32, 35, 33, 34, and 36
Rewrite it from smaller to greater:
32, 34, 34, 35 36.
We notice that the range is from 32 to 36 is only 4 (36-32), Where as the range of the
1st pumpkins is 30-14 = 16
Since the spread of the 1st one is by far larger than the 2nd, we can conclude that the
standard deviation of the 1st is greater than the second
Answer:
3. 100 + 100
5. 1000 + 310
7. 400 + 16
2. 300 + 24
ight that all I can do for you right now
Step-by-step explanation:
