The constant term is found by taking the coefficient of y, dividing it by 2, and squaring the result.
In this case, the coefficient is 1/2. 1/2 of 1/2 is 1/4.
The square of 1/4 is 1/16.
So, the constant term is 1/16.
Answer:
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
Step-by-step explanation:
The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z
Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
Can you put the graph ? I’m kind of a visual person.
Can you be more specific on the problem
