All categories

4 years ago

Write a function rule that relates r and t.

Mathematics

1 answer:

Svetlanka [38]4 years ago

7 0

Answer: $t=-\frac{1}{2}r- 1$

Step-by-step explanation:

For a lineal equation $t=mr+n$

For r=0 and t=-1

$-1=m(0)+n\\n=-1$

For r=-2 and t=0

$0=m(-2)-1\\m(-2)=1\\m=-\frac{1}{2}$

Them $t=-\frac{1}{2}r- 1$

???? The output for 6 is 1????

You might be interested in

If it costs $4.77 for 9 oranges how much would it cost for 1?

Nuetrik [128]

Answer:

1.89

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Describe the correct error -1/4 divided by 3/2=-4/1 multiplied by 3/2= -12/2=-6

malfutka [58]

When dividing fractions you need to multiply the first fraction by the reciprocal of the second. You have done the opposite and multiplied the reciprocal of the first fraction by the second.

4 0

3 years ago

Determine whether the function is linear. If so, give the slope and y-intercept of the function's graph

Olenka [21]

It is not linear, because the x value is cubed, creating a curved line, while a linear line is straight.

4 0

4 years ago

Read 2 more answers

Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries

kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

$\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04$

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535
$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465$

64.65% probability of at least one injury commuting to work in the next 20 years

3 0

3 years ago

At what point will the graphs intersect? y=3x/2-5 and 3x-4y=8

daser333 [38]

Answer:

(4,1)

Step-by-step explanation:

Hope this helps

7 0

3 years ago