Answer:
1a+12/2
Step-by-step explanation:
1/2a+6
1/2a+6/1
1/2a+6/1*2
1/2a+12
1a+12/2
Answer:
(1) .20 (2) .40 (3) .12 (4) Less than
Step-by-step explanation:
You have to look at the table. There are 5 columns with 10 rows. 5x10=50
Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is .
20
The estimated probability that exactly one of the three coins Avery randomly picked is a dime is .
40
The estimated probability that all three coins Avery randomly picked are pennies is .
12
The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.
X/3 - 3/4 = 5/2
x/3 = 3.25
x= 9.75 Or 9 3/4
Pythagoras Theorem is the way in which you can find the missing length of a right angled triangle.
The triangle has three sides, the hypotenuse (which is always the longest), Opposite (which doesn't touch the hypotenuse) and the adjacent (which is between the opposite and the hypotenuse).
Pythagoras is in the form of;
a<em><u /></em>²+b²=c²
However, it can also be written in the form of c²=a²+b²
In order to find the hypotenuse, you will have the length of two sides, for example, these could be 3 and 4.
As 'C' is always the hypotenuse, you have to work out the two other lengths, and you do this by squaring the numbers.
3²=9 and 4²=16.
As you're looking for C, you've got to add these together
9+16=25
As a²+b²=c², this means that the answer for C is the square root of 25.
√25= 5
Hope this has been able to help you :)
