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Rudik [331]
3 years ago
15

Need answer ASAP plz worth 10 points for correct answer only.

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

v would equal 54 i belive

Step-by-step explanation:

natka813 [3]3 years ago
5 0
If you are solving for v, the answer would be -26 . Explanation: you multiply both sides by -3 then you move the constant to the right to get x= -18 - 8. From there you calculate to get -26.
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PLEASE SOMEONE HELP. I’m FAILING MATH . WILL NAME BRAINLIEST AND ITS WORTH 30 points!!
weqwewe [10]
I don’t really understand this put a person with genius role is answering so i hope you get your answer! goodluck
8 0
3 years ago
Read 2 more answers
The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units
Akimi4 [234]

Answer:

The volume of the Prism is equal to the volume of the cylinder

Step-by-step explanation:

Because both are 5 units making them equal

4 0
2 years ago
A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
2 years ago
I have two fair spinners. The first has the numbers 1, 2, 3 and 4. The second has the numbers 2, 3, 4 and 5. I spin both spinner
Snezhnost [94]

Step-by-step explanation:

There are 4 * 4 = 16 outcomes from spinning these spinners. You get an odd number by multiplying an odd number by an odd number. Since there are 2 odd numbers on both spinners the successful outcomes are 2 * 2 = 4 so probability is 4 / 16 = 1 / 4.

3 0
3 years ago
Write the equation of a circle whose center is at the origin and contains the point (2, 3).
Ivanshal [37]

Answer:

x²+y²=13

Step-by-step explanation:

any circle with center at (0,0)

is of the form

x²+y²=r²

find out r²

r² = (2²+3²)=13

so the answer

4 0
3 years ago
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