Rewrite the equation in slope-intercept form
5x -2y = 28
Subtract 5x from both sides
-2y = -5x + 28
Divide both sides by -2
Y = 5/2x -14
The y intercept is -14
They are equivalent
30:12 => 5:2
40:16 => 5:2
hope this helsp
Answer:
not answerable
Step-by-step explanation:
Point-slope form:
y - y₁ = m(x - x₁)
You need to find "m" which is the slope.
To do so, use the slope formula and plug in the two points:
![m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
![m=\frac{7+5}{-3-1} =\frac{12}{-4} =-3](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B7%2B5%7D%7B-3-1%7D%20%3D%5Cfrac%7B12%7D%7B-4%7D%20%3D-3)
m = -3
(x₁ , y₁) = (1, -5)
Plug this into the equation:
y - y₁ = m(x - x₁)
y - (-5) = -3(x - 1)
y + 5 = -3(x - 1)
Slope-intercept form:
y = mx + b "m" is the slope, "b" is the y-intercept
In order to get the equation from point-slope form to slope-intercept form, isolate/get the "y" by itself.
y + 5 = -3(x - 1) First distribute/multiply -3 into (x - 1)
y + 5 = -3x + 3 Subtract 5 on both sides
y = -3x - 2
Answer:
Length of the rectangle is = 8 inches.
Step-by-step explanation:
Given :
Area of square = Area of the rectangle
According to the question:
Length of the square be 'x'.
Its area = (Side)*(Side) =
...equation (i)
Length of the rectangle = ![(x+4)](https://tex.z-dn.net/?f=%28x%2B4%29)
Width of the rectangle = ![(x-2)](https://tex.z-dn.net/?f=%28x-2%29)
Area of the rectangle =Length * Width
⇒![(x+4)(x-2)=x^2-2x+4x-8](https://tex.z-dn.net/?f=%28x%2B4%29%28x-2%29%3Dx%5E2-2x%2B4x-8)
⇒
...equation (ii)
Equating both the equation as area of both the figure are equal.
⇒ ![x^2+2x-8=x^2](https://tex.z-dn.net/?f=x%5E2%2B2x-8%3Dx%5E2)
⇒
...subtracting
both sides
⇒
...dividing both sides with 2
⇒
inches
Plugging the value of x=4 in the length of the rectangle.
We have,
⇒![(x+4)=(4+4)=8](https://tex.z-dn.net/?f=%28x%2B4%29%3D%284%2B4%29%3D8)
So the length of the rectangle = 8 inches.