Question

Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of the youngest is twenty-four less than the middle brother's age Find their ages.

Answer 1

N, N+2, and N + 4 are the ages

(N + 4) - (2N) = (N + 2) -24

4 - N = N - 22

2N = 26

N = 13

The brothers are 13, 15, and 17 years old.

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