Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of th
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1. We are given:
The only a which squared gives you 64 is 8. The perimeter of an 8 by 8 square will be 32. Half of that is 16. Now, let's see what we can do. We can set up:
Obviously, each side length has to be 4. So, the area of this square will be 16 units².
2. Let n equal her son's age. So, her age right now will be (S = her age):
1 year ago it was:
We have 2 equations, let's substitute. We can rewrite this as:
Solve for n:
We know the value of n, which is her son's age. So, her son is 1/15 of a year old or about 24 days old.
The only a which squared gives you 64 is 8. The perimeter of an 8 by 8 square will be 32. Half of that is 16. Now, let's see what we can do. We can set up:
Obviously, each side length has to be 4. So, the area of this square will be 16 units².
2. Let n equal her son's age. So, her age right now will be (S = her age):
1 year ago it was:
We have 2 equations, let's substitute. We can rewrite this as:
Solve for n:
We know the value of n, which is her son's age. So, her son is 1/15 of a year old or about 24 days old.