A basketball player’s free throw percentage is 70%. She has just been awarded 3 free throws after getting fouled on a 3-point sh
ot. Which table shows the correct probability distribution for the possible numbers of free throws made?
2 answers:
Answer:
.34
Step-by-step explanation:
<span>P(3 Free Throws) = P(One Free Throw & One Free Throw & One
Free Throw)
P(3 Free Throws) = P(One Free Throw) x P(One Free Throw) x P(One Free Throw)
P(3 Free Throws) = (7/10) x (7/10) x (7/10)
P(3 Free Throws) = (7x7x7)/(10x10x10)
P(3 Free Throws) = 343/1000 </span>
<span>
P(3 Free Throws) = 0.343
The probability is 0.343 to make all 3 free throws. </span>
<span> </span>
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