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NISA [10]
3 years ago
13

A basketball player’s free throw percentage is 70%. She has just been awarded 3 free throws after getting fouled on a 3-point sh

ot. Which table shows the correct probability distribution for the possible numbers of free throws made?

Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0

Answer:

.34

Step-by-step explanation:

Vlada [557]3 years ago
6 0

<span>P(3 Free Throws) = P(One Free Throw & One Free Throw & One Free Throw) 


P(3 Free Throws) = P(One Free Throw) x P(One Free Throw) x P(One Free Throw) 


P(3 Free Throws) = (7/10) x (7/10) x (7/10) 


P(3 Free Throws) = (7x7x7)/(10x10x10) 


P(3 Free Throws) = 343/1000 </span>

<span>

P(3 Free Throws) = 0.343 


The probability is 0.343 to make all 3 free throws. </span>

<span> </span>

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