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ycow [4]
3 years ago
11

Square A is a scaled version of square B. The dimensions of square A are three times the dimensions of square B. The area of squ

are A is 900 sq cm.
Mathematics
1 answer:
denis23 [38]3 years ago
8 0

Answer:

The side of square A is 30 cm.

Step-by-step explanation:

Given that,

The dimensions of square A are three times the dimensions of square B.

The area of square A is 900 sq cm.

Side of square A = 3( side of square B)

Let the side of square B is b. So,

Side of square A, a = 3b

We know that, the area of square is side². So,

(3b)^2=900\\\\9b^2=900\\\\b^2=100\\\\b=10\ cm

Side of square A, a = 3(10) = 30 cm

Hence, the side of square A is 30 cm.

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carlos and Jacob each improve their yards by planting daylilies and ivy. They bought their supplies from the same stores. Carlos
34kurt

Answer:

Cost of each daylilies = $3

Cost of each ivy pot = $3

Step-by-step explanation:

Given:

Cost of 4 daylilies and 4 ivy = $24

Cost of 4 daylilies and 8 ivy = $36

Find:

Cost of each daylilies

Cost of each ivy pot

Computation:

Assume;

Cost of each daylilies = a

Cost of each ivy pot = b

So,

4a + 4b = 24....... eq 1

4a + 8b = 36 ....... eq 2

Eq2 - Eq1

8b - 4b = 36 - 24

4b = 12

b = 3

So,

Cost of each ivy pot = $3

4a + 4b = 24

4a + 4(3) = 24

4a + 12

a = 3

Cost of each daylilies = $3

6 0
3 years ago
What is the simplified form of √144x^36
Nadusha1986 [10]

Answer:

The simplified form of \sqrt{144x^{36}} is 12x^{18}

Step-by-step explanation:

Given : \sqrt{144x^{36}}

We have to write the simplified form of \sqrt{144x^{36}}

Consider the given expression \sqrt{144x^{36}}

We know \sqrt{144}=12

and \sqrt{x^{36}}=\sqrt{x^{18}\cdot x^{18}}

Thus,

\sqrt{144x^{36}}=\sqrt{12^2\cdot (x^{18})^2}

Simplify, we have,

=\sqrt{12^2\cdot (x^{18})^2}=12x^{18}

Thus, The simplified form of \sqrt{144x^{36}} is 12x^{18}

6 0
3 years ago
Read 2 more answers
For a moving object, the force acting on the object varies directly with the objects acceleration. When the force of 63 N acts o
Serjik [45]

Answer:

49N

Step-by-step explanation:

Step one

Given

When the force of 63 N acts on a certain object

the acceleration of the object is 9/ms^2

Firstly, we need to calculate the mass m

F=ma-------1

m= F/a

m= 63/9

m= 7kg

Step two:

Also, if the acceleration of the object becomes 7 m/s^2

then the force

Note: the mass remains the same= 7kg

F=ma

F=7*7

F= 49N

4 0
2 years ago
Please Help I Need The Awnsers
Law Incorporation [45]

x= 113°

hope that helps^^

8 0
3 years ago
7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)
artcher [175]

Answer with explanation:

The equation of line is, y= -x +3

→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

  x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular  to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

  x-y+k=0

The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

4 0
2 years ago
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