Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
(x² + 4x + 2)(2x² + 3x - 4) equals 2x⁴ + 11x³ + 12x² - 10x - 8
Step-by-step explanation:
<em>(x² + 4x + 2)(2x² + 3x - 4)</em>
Multiply each term in the first parentheses into the expression in the second parentheses.
<em>2x⁴ + 3x³ - 4x² + 8x³ + 12x² - 16x + 4x² + 6x - 8</em>
Combine like terms.
<em>2x⁴ + 11x³ + 12x² - 10x - 8</em>
So, your answer would be letter choice B.
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If 100 miles = 1 in.
650 = 6.5 x 100 and 6.5 x 1 = 6.5
so, if the journey is 650 m...... the map is 6.5 in.
It is 28 pounds. This is because all of the others have a ratio of 4:1 while 28 and 5.5 have a ratio of 56:13.
Add 11 to both sides:
-4=-2t
divide 2 by both sides
2=t
Hope it helps! Comment if you have any questions!
