Because the left side is eclipsed in an absolute value, we have two possible values of x, denoted by:
2x+4 = 12 and -(2x+4) = 12
Solving for both of these, we are presented with the two values of x:
x = 4 and x = -8
Let x be the angle. The complement is 3x + 10. The sum of two complementary angles is 90. So,
x + 3x + 10 = 90
4x + 10 = 90
4x = 80
x = 20
Plug x into the complement
3(20) + 10 = 70
The angle is 20 degrees and the complement is 70 degrees
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
G(x) = 3x + 1, evaluate g(-2).
Simply plug in (- 3) in g(x)
g(-2) = 3(-2) + 1
g(-2) = - 6 +1
g(-2) = - 5
Answer:
The value of x is 
Step-by-step explanation:
we know that
Applying the tangent-secant theorem
substitute the values and solve for x
using a graphing tool
to solve the quadratic equation
The solution is 
see the attached figure
