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Elan Coil [88]
3 years ago
15

What is -7(w+6)^2+21=0.​

Mathematics
1 answer:
adoni [48]3 years ago
8 0
After solving for w using inverse operations, w would have to equal 5.74 to make this equation true.
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What is the Lcm of 2 and 7
wel

Answer:

14

Step-by-step explanation:

The least common multiple is a number that both numbers can multiply something to get to, and the smallest possible common one.

Let's try listing out the multiples of 2:

2, 4, 6, 8, 10, 12, 14, 16, 18, 20

And the multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70

Notice that both have the number 14 in common, and it is the first number that they do so.  There are lots of other multiples that they have in common too, but 14 is the least.

5 0
2 years ago
How did the musician keep his sousaphone clean?
Sedbober [7]
  the answer  in the attached figure

8 0
3 years ago
Read 2 more answers
There are two parking garages in beacon falls . Garage a charges $7.00 to park for the first 2 hours ,and each additional hour c
Julli [10]

Answer

Find out the number of hours when the cost of parking at both garages will be the same.

To prove

As given

There are two parking garages in beacon falls .

As given

Let us assume that the y is representing the  cost of parking at both garages will be the same.

The total number of hours is represented by the x.

First case

Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .

As  garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)

Than the equation becomes

y = 3.00 (x -2) + 7.00

written in the simple form

y = 3x - 6 +7

y = 3x + 1

Second case

Garage b charges $3.25 per hour to park.

than the equation becomes

y = 3.25x

Compare both the equations

3x +1 = 3.25x

3.25x -3x = 1

.25x = 1

x = \frac{1}{.25}

x = 4hours

Therefore in the 4 hours  the cost of parking at both garages will be the same.



3 0
3 years ago
rectangular solid that is 6-cm-by-6 cm-by-6 cm is painted on all six faces. then the solid is cut into cubes that measure 2 cm o
Nitella [24]
If you check the picture below

the rectangular solid is a 6x6x6, so all sides are equal thus is a cube

is painted on all faces, so the only part that's painted is the faces, ok
then you split it like in the picture, you have all 6 faces painted there,

now, let's say each of those 6 faces are cut in 2cm

how many of those 2cm pieces will each have?   so get that amount for each and sum them up, that's how many of the cubes have one face painted

only the cubes that are part of the face, which was painted, are the ones that have a painted face themselves

keep in mind that each face is a 6x6 rectangle
notice the 2nd picture below

6 0
3 years ago
Read 2 more answers
Factor sec^2x-secx+tan^2x
marysya [2.9K]

Answer:

sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)

Step-by-step explanation:

sec²(x) - sec(x) + tan²(x) =

= sec²(x) - sec(x) + [sec²(x) - 1]

= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]

= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]

= (sec(x) - 1)(sec(x) + sec(x) + 1)

= (sec(x) - 1)(2sec(x) + 1)

6 0
3 years ago
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