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3 years ago

A partir del resultado obtenido ;con

Mathematics

1 answer:

Ymorist [56]3 years ago

8 0

Answer:

I don't understand what your asking here.

Your translation: From the result obtained; with

Step-by-step explanation:

You might be interested in

To earn money for a contest, the math team pays $40 for a box of spirit banners. They sell each banner for $3.50. Write an equat

ankoles [38]

Answer:

$3.5b - 40$ where $b$ is the amount of banners sold.

Step-by-step explanation:

We know the team has already spent $40, and they earn #3.5 per banner.

Hence, with $b$ representing the amount of banners sold, the equation is $3.5b - 40$

7 0

3 years ago

PLEASE ANSWER!!!!!! REALLY IMPORTANT

faust18 [17]

Answer-

The height of the prism is 6 units

Solution-

As the base of the prism is a hexagon consisting of 2 congruent isosceles trapezoids.

So,

$V_{Prism}=Area_{Base}\times Height$

And,

$Area_{Base}=2\times \text{Area of the trapezoid}$

Also,

$\text{Area of the trapezoid}=\dfrac{1}{2}\times \text{Height}\times (\text{Sum of two parallel lines})$

$=\dfrac{1}{2}\times 3\times (5+8)\\\\=\dfrac{39}{2}$

Putting all the values,

$V_{Prism}=2\times \dfrac{39}{2}\times Height=39\times Height$

As the volume is given, so

$\Rightarrow 39\times Height=234$

$\Rightarrow Height=\dfrac{234}{39}=6$

8 0

3 years ago

Read 2 more answers

Which is the best estimate of the sum of the fractions 5/12+5/9

Bumek [7]

Answer:

0.926

Step-by-step explanation:

5/12 as a decimal is 0.416 and

5/9 as a decimal is 0.5 repeating

You just have to turn the fraction into a decimal and

add those together.

So your final equation would be 0.416+0.5

8 0

3 years ago

Read 2 more answers

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

7 0

3 years ago

Pia printed two maps of a walking trail. The length of the trail on the first map is 8 cm. The length of the trail on the second

Vlada [557]

Scale :

Map 1 : Actual
1 cm : 2 km
1 cm : 200 000 cm | Convert 2km to 200 000cm

Answer: The scale is 1 : 200 000

Map 1 : Actual
1 cm : 200 000 cm
(x8) : (x8)
8 cm : 1 600 000cm

1 600 000 cm = 16 km

Answer: The length of the actual trail is 16 km

Map 1 : Map 2
8cm : 6cm
1cm : 0.75 cm

Answer : The scale is 1 : 0.75

Map 1 : Map 2
1 : 0.075

3mm : 0.075 x 3 = 0.225mm

4mm : 0.075 x 4 = 0.3 mm

5mm : 0.075 x 5 = 0.375 mm

Answer: The side lengths are 0.225mm, 0.3 mm and 0.375 mm

3 0

3 years ago

A partir del resultado obtenido ;con​

A partir del resultado obtenido ;con