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3 years ago

Solve the system of equations13х – 6у = 22 x=y+6

Mathematics

1 answer:

Mrrafil [7]3 years ago

4 0

Answer:

x = -2, y = -8

Step-by-step explanation:

13(y + 6) - 6y = 22

=> 13y + 78 - 6y = 22

=> 7y = -56

=> y = -8

x = -8 + 6

=> x = -2

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A video game store made a display of game console boxes show at the right. the length, width and high of each game console box i

yulyashka [42]

The volume would be 8ft because the formula for volume is length x width x height. Since they are all 2ft the formula would be 2ft x 2ft x 2ft.

4 0

2 years ago

35 + (45+ 25) = (35 +45) +25 which property is this

Dafna1 [17]

Answer:

Associative Property

Step-by-step explanation:

Commutative: 35+(45+25) = (25+45)+35

Associative: 35+(45+25) = (35+45)+25

Distributive: cannot be done

hope this helps!

8 0

2 years ago

Elliott is 63 inches tall, which is 9inches taller than cousin, Jackson.write and solve an addition equation to find Jackson hei

Nataly [62]

Answer:

J + 9 = 63

Jackson = 54 inches

Step-by-step explanation:

Using the variable 'J' for the height of Jackson, we know that Elliott is Jackson's height, plus an additional 9 inches. Since Elliott is 64 inches tall in total, we can add Jackson's height plus 9 to get Elliot's height:

Jackson's height + 9 inches = Elliot's height

J + 9 = 63

Subtract '9' from both sides: J + 9 - 9 = 63 - 9 or J = 54

So, Jackson is 54 inches tall.

3 0

2 years ago

Find a function where f(0)=2 and f(1)=2

xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

$f(x) = x^2-x+2$

Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need $A= 2$ , and at that point the first condition is guaranteed; using the second to find k we get $2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi$