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kupik [55]
3 years ago
13

Can someone pretty please help me ? :)

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

Yes C is correct

Step-by-step explanation:

Because I did this in class

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How to find the factor of a trinomial?
BaLLatris [955]
I can tell you about the 'ac' method of factoring trinomials by way of an example:-

Factor   3x^2 - 4x - 15

first multiply the first number by the last  That is 3 * -15   = -45

Now we need to find  2 factors of -45 which will when added give - 4 ( the coefficient of x)

-9 and = 5  look like the  ones so we write

3x^2 - 9x + 5x - 15

 Now  factor this by grouping:-

= 3x(x - 3) + 5(x - 3)

x - 3 is common to the 2 parts so we have:-

(3x + 5)(x - 3)  <-------- These are your  factors

Any trinomial can be factored in this way.
6 0
4 years ago
P=-3w+9 <br><br><br><br>tell me the steps I already have the steps
anastassius [24]
You're solving for w for I assume.

P= -3w+9, put -3w on the left side and P on the right side.
3w= -P+9, divide both sides by 3.
w= -P+9 over 3.
w= -P over 3 plus  9 over 3.
(Final Answer):
w= -p over 3 plus 3.

Hope this helps. 
4 0
3 years ago
A can of peas weighs 10 oz. Explain how you would make a graph to model the total weight of peas in terms of the number of cans
Vika [28.1K]
Ur x axis will be the number of cans and ur y axis will be the weight in oz

u will label ur x axis( the number of cans) in intervals of 1......from 0 to 4
u will label ur y axis (the weight) in intervals of 10....from 0 to 40

ur equation would be : y = 10x
points on this line are : (0,0), (1,10), (2,20), (3,30), (4,40)
3 0
3 years ago
Read 2 more answers
Ments
maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

#SPJ1

8 0
2 years ago
And an equation of the line. Write the equation using function notation.
NeTakaya

Answer:

F(x) = - 2/5x - 11

Step-by-step explanation:

F(x) = - 2/5x + c

-9 = - 2/5(-5) + c

-9 = 2 + c

- 11= c

F(x) = - 2/5x - 11

7 0
3 years ago
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