Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get


Hence amount owed at the end of 1 year is 3640
Answer:
x = 8^3
Step-by-step explanation:
To rewrite an equation with logs in exponential form, you need to know
logb(a) = m is equivalent to a= b^m
So given log8 (x) = 3 is equivalent to x = 8^3
Answer:
To find the x-intercept, substitute in 0 for y and solve for x
. To find the y-intercept, substitute in 0 for x and solve for y
.
x-intercept: (−
45
,
0
)
y-intercept: (
0
,
−
15
)
The correct answer is letter D, Region D contains the solution for the system of inequalities.