1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GalinKa [24]
2 years ago
11

What is the circumference of a circle with a diameter of 9 cm?

Mathematics
1 answer:
Kamila [148]2 years ago
5 0

Answer:

the answer=28.27cm

using formula

c=2πr

d=2r

solving for c

C=πd

=π.9

=28.27

hope it help you

You might be interested in
Show how you can use repeated subtraction to find 84 divided by 6\
prisoha [69]
You can use repeated subtraction to solve 84 divided by 6 by subtracting 6 from 84 repeatedly, and stopping until either you reach zero, or until you cannot make any more groups of 6.
6 0
3 years ago
Read 2 more answers
HELP HELP WILL MARK RIGHT AND FIRST ANWSSER BRANLIEST
Liono4ka [1.6K]
It should be option A! I hope this helps you!
5 0
3 years ago
78 divided 21 please answer with the remainder
Gnesinka [82]

Answer:

3.7142

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(25pts) Due soon! Help!
navik [9.2K]

Answer:

true

True

False

False

Step-by-step explanation:

a. The problem tells me that for every 3 parts of red paint, I have 8 parts of yellow paint. To find the ratio of 1 part of yellow paint I can write the following statement

For 8 parts of yellow paint ------------ 3 parts of red paint

        1 part of yellow paint  -------------      x

So x=\frac{1 part of yellow paint * 3 parts of red paint }{8 parts of yellow paint}

x= \frac{3}{8} parts of red paint

b, I have the following relationship

3 parts of red paint ----- 8 parts of yellow paint

If I multiply the entire expression by 3 I have left

3 * 3 parts of red paint -------- 8 * 3 parts of yellow paint

So

9 parts of red paint ---------- 24 parts of yellow paint

c.I have the same relationship

3 parts of red paint ----- 8 parts of yellow paint

If I multiply the entire expression by 1/2 I have left

3/2 parts of red paint -------- 8/2 parts of yellow paint

So

3/2 parts of red paint ---------- 4 parts of yellow paint

as 3/2 is different from 10, then the approach is false

d. observing the relation of part a,

For 3 parts of red paint ------------ 8 parts of yellow paint

      1 part of red paint   -------------      x

So x=\frac{1 part of red paint * 8 parts of yellow paint }{3 parts of red paint}

x= \frac{8}{3} parts of yellow paint  that is different than 3/8 parts of yellow paint, then the approach is false

6 0
3 years ago
Read 2 more answers
Help me please!!!!!!!
xxTIMURxx [149]
Hmm, Its pretty blurry and nice cat but I will try for ya :D ***cant gurantee its gonna be correct***

6 3/4 =27/4
2/3= 0.666666666 (0.66)
1 3/4= 7/4
2 1/4 = 9/4

(i can't solve this im so sorry holy shoot)
7 0
3 years ago
Other questions:
  • Izabella has an account balance of more than -$6. Is her debt greater than or less than $6? Explain.
    8·2 answers
  • F(x)= -2x + 2; Find f(5)
    15·1 answer
  • the stained glass below shows bilateral symmetry. The two overlapping squares are congruent. What is the area of the window?
    8·1 answer
  • Find all values of $x$ such that $\dfrac{x}{x+4} = -\dfrac{9}{x+3}$. If you find more than one value, then list your solutions i
    9·2 answers
  • Alex runs 3 laps around a course that is 1 3/4 miles long how far did he run?
    5·1 answer
  • 6x - 2y = -22<br> х+4y = -8
    10·2 answers
  • Find the coefficient of the third term in the expansion of (2x+y)^5
    6·1 answer
  • Caps in the mall is having a 40% off sale on all baseball hats. Mary paid $12 for her favorite hat that was on sale. What was th
    9·1 answer
  • Which of these lines is perpendicular to the line y = 3x + 2?
    6·1 answer
  • A company's sales equal $60,000 and cost of goods sold equals $20,000. Its beginning inventory was $1,600 and its ending invento
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!