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Fofino [41]
3 years ago
7

In Niagara-on-the-Lake, you can ride a horse-drawn carriage for a fixed price plus a variable amount that depends on the length

of the trip. The variable cost is $10/km and a 2.5-km trip costs $40. a) Determine the equation relating cost, C, in dollars, and distance, d, in kilometres. b) Use your equation to find the cost of a 6.5-km ride. c) Graph this relation. d) Use the graph to find the cost of a 6.5-km ride.

Mathematics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

Step-by-step explanation:

a) The cost of a product is given as:

Cost = a + bx

Where a is the fixed cost, b is the variable cost, x is the independent variable.

In this case, the independent variable is the distance(d), therefore:

Cost (C) = a + bd

C = a + bd

But the variable cost is $10/km, therefore:

C = a + 10d

A 2.5 km trip cost $40, therefore:

40 = a + 10(2.5)

40 = a + 25

a = 40 - 25 = 15

The fixed cost is $15. Therefore the equation for cost is:

C = 15 + 10d  

b) C = 15 + 10d  

For 6.5 km ride:

C = 15 + 10(6.5) = 15 + 65 = 80

It would cost $80 for a 6.5 km drive.

 

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θ is the angle from a standard position of the line OA

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Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent

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θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3

α= arcsin(1/√10) ≈ 18
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a. See attachments

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Check attachments for details

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