You can use spearman’s rank correlation coefficient but not sure if that’s the answer your looking for because it looks like you haven’t gave the whole question
Answer:
Yes, P(A) = P(A|B)
Step-by-step explanation:
The context of the question is incomplete but I've assumed logically what it might be;
Whether a traveller flies or doesn't fly to their destination is unrelated to whether they home share or not;
Therefore, they are independent;
Independent events are events where the outcome of one event has no effect on the probabilities of the outcomes from a second event;
This can be represented mathematically as: P(A) = P(A|B);
The corollary of this is P(B) = P(B|A);
A common example easily understood would be if you flip a coin, there is a 50% chance of heads and 50% chance of tails;
If I flip and gets a heads first, the probability of getting a heads or tails on the second, third or tenth flip is going to be unchanged, i.e. 50% chance of heads and 50% chance of tails
Answer:
the velocity would be 40.5
Step-by-step explanation:
The statistical question would be B.
The rectangle would have a width of 32 cm and height of 16