Answer:
Your answer for this is D
Answer:
Options 2, 3 and 4
Explanation:
Options 2, 3 & 4 are also mentioned at tge end of the cycle; hence it means that a star can become a supernova, black hole or a neutron star at the end of its evolution.
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To know what happens here, you need to analyze the alleles.
If the father is color blind and the daughter is not, you can suppose that is a recessive allele.
You can tell she is a carrier only, and because we received one sexual allele from each parent. If they ask you about the gender, we can suppose a cross between Xx and XY being lower x the recessive allele (color-blind vision).
When you draw the Punnett square, you'll found the probabilities are XX, XY, Xx, and xY.
So, you have a 50% chance of having a boy and 25% chance of having a color-blind boy.
Answer:
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Explanation:
The genotype of a color-blind man is X^cY and the genotype of the heterozygous carrier female is X^cX. A cross between X^cY and X^cX would produce a progeny in following ratio=
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Therefore, the couple is likely to have 50% normal son and 50% affected son. Likewise, the couple is likely to have 50% normal daughters and 50% colorblind daughters.
<span>The place where two bones meet and allow our skeletons to be more flexible is known as a Joint.</span>
