615 - 6 = 609
963 - 6 = 957
609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.
Answer:
Option E) is correct
If n is an odd number then 2(n+1) represents an even number.
Step-by-step explanation:
Let X=set of all odd numbers
that is 
Let Y=set of all even numbers
that is 
Verify that 2(n+1) represents an even number where n is an odd number:
Put n=1 in 2(n+1) we get
2(1+1)=2(2)=4
Put n=3 in 2(n+1) we get
2(3+1)=2(4)=8
Put n=5 in 2(n+1) we get
2(5+1)=2(6)=12
and so on.
From above results we get 2(n+1) represents an even number and is belongs to the set Y when n is an odd number.
Therefore Option E) is correct
If n is an odd number then 2(n+1) represents an even number.
C, and D. They’re parallel so they’re never going to cross.
Answer:
i tihnk 11 is 86 sorrry if im wrong
Step-by-step explanation:
Answer:
They are both correct because there is more than one way to write a multivariable polynomial in standard form. Marcus has the exponents on the x variable in descending order from the highest degree to the lowest degree. Ariel has the exponents on the y variable in descending order from the highest degree to the lowest degree.