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erica [24]
2 years ago
8

What Values of X Makes these equations true? Label Them as 1. 2.

Mathematics
2 answers:
maks197457 [2]2 years ago
4 0

Answer: your answer is answer

Step-by-step explanation; the physics of the calculations say you are not einstien.

Mars2501 [29]2 years ago
3 0
Can’t answer make sure ask an expert
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It is given that in △ABC, AD ⊥ BC. Using the definition of sine with angle C in △ACD results in sin(C) = . Using the multiplicat
amid [387]

We see here in the diagram that the base is a. We know this because the height is perpendicular to it. We also know the height is bsin(C) which, when replace h for bsin(C) and a for the base, we get A=absin(C), which is the second option.

7 0
3 years ago
Read 2 more answers
N.p + p for n = 3 and p = 6
zheka24 [161]

Answer:

Hey there!

3.6+6

9.6

Let me know if this helps :)

4 0
4 years ago
What does the fact that the expressions are equivalent mean?
NNADVOKAT [17]

Answer:

The fact that the expressions are equivalent means that for any value of the variables, the two expressions have the same solution.

Step-by-step explanation:

3 0
3 years ago
At present the sum of Monica's age and daughter's age is 44 years. . After 2 years Monica's age will be three times that if her
sergeinik [125]

Answer:

Monica's age = 34 years

Her daughter's age = 10 years

Step-by-step explanation:

Let Monica's age = x

Let her daughter'sage = y

x + y = 44   -------> equ 1

After 2 years:

Monica's age = x + 2

Her daughter's age = y + 2

x + 2 = 3 * (y+2)

x + 2 = 3y + 6

      x = 3y + 6 -2

      x = 3y + 4

Put x value in equ 1:

    3y + 4 + y = 44

            4y = 44 - 4

             4y = 40

               y = 40/4

               y = 10

x = 44 -10

x = 34

7 0
3 years ago
Read 2 more answers
preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha
VladimirAG [237]

Answer:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

n=369

Step-by-step explanation:

1) Notation and definitions

X=40 number of the selected labourers opt for a new incentive scheme.

n=100 random sample taken

\hat p=\frac{40}{100}=0.4 estimated proportion of the selected labourers opt for a new incentive scheme.

p true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

And rounded up we have that n=369

8 0
3 years ago
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