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3 years ago

Which of these is the absolute value parent function?

Mathematics

1 answer:

wel3 years ago

8 0

Answer:

option d.

 f(x) = |x| is the absolute value parent function.

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Find the exterior angle of a regular decagon

mamaluj [8]

Answer:

Exterior Angle = 36 degrees

Step-by-step explanation:

Each interior angle of a regular decagon measures 144 degrees.

=> We'll subtract 144 from 180 to get the measure of the exterior angle.

=> Exterior Angle = 180-144

=> Exterior Angle = 36 degrees

6 0

3 years ago

Erin buys a bag of peanuts that weighs 3/4 of a pound.later that week the bag is 2/3 full how much does the back of peanuts weig

nasty-shy [4]

The answer is 1/2lbs, here's how.

3/4x2/3=6/12 reduced to 1/2lbs.

4 0

3 years ago

If you take a number, times by 7 then subtract 1. You get the same as if you took the number multiply the number by 5 then subtr

Irina-Kira [14]

Answer:

-7/2 or -3.5

Step-by-step explanation:

Make the equation first

7x-1 = 5x-8

7 = -2x

-7/2 = x

4 0

3 years ago

Read 2 more answers

If the points at (-4, 3) and (2, 3) are reflected over the x-axis to create two new points, what shape can be formed by the four

Svetllana [295]

Answer:

Step-by-step explanation:

Let $(a,b)\in \mathbb{R}^{2}$ , a reflection over the x-axis consists in the following operation:

$(a,b) \rightarrow (a,-b)$

If we know that $X = (-4,3)$ and $Y = (2, 3)$ , then the points translated over the x-axis are $X' = (-4, -3)$ and $Y' = (2,-3)$ , respectively. The most precise description of the shape is a rectangle for the following facts:

1) $XX' = YY' = 8$ and $XY = X'Y' = 6$ .

2) $X$ and $X'$ have the same x-component.

3) $Y$ and $Y'$ have the same x-component.

4) $X$ and $Y$ have the same y-component.

5) $X'$ and $Y'$ have the same y-component.

A representation of the shape is included below as attachment.

3 0

3 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship $\sin{\theta} < \cos{\theta}$ holds for all acute angles? (That is, $0^{\circ} < \theta$ ?) It turns out that:

$\sin{\theta} < \cos{\theta}$ if $0^{\circ} < \theta$ ;
$\sin{\theta} > \cos{\theta}$ if $45^{\circ} < \theta$ ;
$\sin{\theta} = \cos{\theta}$ if $\theta = 45^{\circ}$ .

4 0

3 years ago

Read 2 more answers