Solution :
Let us consider the squares be ![$[1, 16] \times [16, 32]$](https://tex.z-dn.net/?f=%24%5B1%2C%2016%5D%20%5Ctimes%20%5B16%2C%2032%5D%24)
If x ranges from the 0 to 16 and the y ranges from 16 to 32, we see that the boundary of the region
which goes from the 
.
And so it is easier to find the area of region where 
. This is the triangle with points 
as its vertices.
The area if the triangle is = 
= 
Now the entire area is 
= 256
Then, 
or 
Thus the answer is 
Answer:
B
Step-by-step explanation:
This is a power to a power problem. -3 times 2 equals-6. Usually when a number is raised to a negative power, the number is the denominator over 1...with the exponent in the denominator ad well. 5 to the -6 power is 15,605 which is the same as 1/5 to the 6th power....1/15,605
=(x^8 - x + 7) + (9x^8 + 6)
Combine like terms
=(x^8+9x^8)-x+(7+6)
=10x^8-x+13
D) 10x^8-x+13 is the answer.
Hope this helps! :)
Answer:
4. AC = 36
5. m<UTW = 42
Step-by-step explanation:
4.
AB = BC
-x + 25 = 3(2x - 8)
-x + 25 = 6x - 24
-7x = -49
x = 7
AC = 2(-x + 25) = 2(-7 + 25) = 2(18) = 36
AC = 36
5.
2x + 3 = 5x - 24
-3x = -27
x = 9
m<UTW = 2m<UTV = 2(2x + 3) = 2[2(9) + 3] = 2(21) = 42
m<UTW = 42
