X is equal to 19. Hoped this helped
<span>Solving the equation for Y = 1.
5 * (3 * 1 - 2) = 15 * 1 - 10
5 * (3 - 2) = 15 -10
5 * 1 = 5
5 = 5
Solving the equation for Y = 2.
5 * (3 * 2 - 2) = 15 * 2 - 10
5 * (6 - 2) = 30 -10
5 * 4 = 20
20 = 20
Solving the equation for Y = 4.
5 * (3 * 4 - 2) = 15 * 4 - 10
5 * (12 - 2) = 60 -10
5 * 10 = 50
50 = 50
Solving the equation for Y = 8.
5 * (3 * 8 - 2) = 15 * 8 - 10
5 * (24 - 2) = 120 -10
5 * 22 = 110
110 = 110
Solving the equation for Y = 9.
5 * (3 * 9 - 2) = 15 * 9 - 10
5 * (27 - 2) = 135 -10
5 * 25 = 125
125 = 125
This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9.
However, it can be proved that the equation holds good for any value of y.
Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided.
So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
Answer:
a
Step-by-step explanation:
Answer:
The required probability is 4/7.
Step-by-step explanation:
The sample space for the experiment is: { BB, BR, RB, RR }
The outcome of the event we require is: { BR, RB }
The probabilities for each outcome is given as:
BB: 3/7 x 2/6 = 1/7
BR: 3/7 x 4/6 = 2/7
RB: 4/7 x 3/6 = 2/7
RR: 4/7 x 3/6 = 2/7
Adding the probabilities we have:
{ BR, RB} = 2/7 + 2/7 = 4/7
That's it!
Answer:
16
Step-by-step explanation:
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