Answer:
$17 on food per person
Step-by-step explanation:
The cost of parking a car is $5
Assuming that the friends used one car, then the parking cost=$5
Admission cost is 19
For three people, Admission cost =19*3=57
TOTAl COSTS=Parking cost+Admission cost
TOTAl COSTS=57+5=62
Remaining amount can be used for food
FOOD= 113-62=51
Therefore each person can spend 51/3=$17 on food
I hope this was helpful and clear to follow
Answer: the original price of the skirt is $24
Step-by-step explanation:
Let x represent the original price of the skirt. if the original price of the blouse is 18, then the original price of the skirt and blouse is (x + 18)
Jade buys a blouse and a skirt for 3/4of their original price. It means that the amount at which she bought the skirt and blouse is
0.75(x + 18)
Applying the distributive property, it becomes
0.75x + 13.5
Jade pays a total of 31.50 for the two items. It means that
0.75x + 13.5 = 31.5
0.75x = 31.5 - 13.5
0.75x = 18
x = 18/0.75
x = $24
Answer: alternate interior angles
Step-by-step explanation:
Got it Right on the test. :)
Let x be equal to the number of drinks Yasmine consumed.
Jose had 2 times that drink so his number of consumed drink would be represented by 2x.
Sally had 3 fewer drink than Jose so her number of consumed drinks would be represented by 2x-3.
Altogether, the three of them consumed 72 drinks so your equation would be:
x+2x+(2x-3)=72
add like terms together:
5x-3=72
have the term with x be alone on one side of the equation, in this case by adding three to both sides:
5x=75
now divide both sides by five for the value of x and your answer is.....
x=15
Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
