6th grade math help me please :(

HACTEHA [7]

4 = amount

8 = base 

amount / base = percent 

4 / 8 = 0.50 

multiply 100 times the decimal and attact he % symbol 

100 x 0.5 = 50 % 

4 is 50% of 8

5 0

3 years ago

Does anyone know how to solve this? I would really appreciate help.

Bess [88]

Answer:

Step-by-step explanation:

The intersection point (centroid) divides the medians in ratio 2:1. it does mean that the long segment value is the short segment value multiplied by two. let's call the centroid point G.

BG=DG*2=4*2=8

CG=EG*2=2*2=4

AG=FG*2 =>FG=AG/2=6/2=3

4 0

3 years ago

Help me please,Thanks

alukav5142 [94]

I have not done measurements in a really long time and i am most likely wrong but i think its 45

8 0

4 years ago

At a time denoted as t = 0 a technological innovation is introduced into a community that has a fixed population of n people. De

ehidna [41]

N = number of people = constant

number of people who have adopted the new technology: x(t) = x

number of people who have not adopted the new technology: n - x

proportionality constant: k

dx / dt = kx(1-x)

x(0) = 0 (this is at t = 0, 0 people have adopted the new technology)

5 0

4 years ago

Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply. To begin conver

umka21 [38]

Answer:

1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.

Step-by-step explanation:

Let prove the validity of each choice:

1) To begin converting the equation to standard form, subtract 36 from both sides:

Let consider the following formula and perform the following algebraic operations:

(i) $x^{2} + y^{2} + 4\cdot x - 6\cdot y - 36 = 0$ Given

(ii) $x^{2} + 4\cdot x + y^{2} - 6\cdot y - 36 = 0$ Commutative Property

(iii) $(x^{2} + 4\cdot x + 4) - 4 + (y^{2} - 6\cdot y + 9) - 9 -36 = 0$ Modulative/Associative Property/Additive Inverse Existence

(iv) $(x+ 2)^{2} - 4 + (y - 3)^{2} - 9 - 36 = 0$ Perfect Trinomial Square

(v) $(x+2)^{2} +(y-3)^{2} = 4 + 9 + 36$ Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property

(vi) $(x+2)^{2} + (y-3)^{2} = 49$ Definition of Addition/Result

False, to begin converting the equation to standard form, each side must be added by 36.

2) True, step (iii) on exercise 1) indicates that both side must be added by 4.

3) The general equation for a circle centered at (h, k) is of the form:

$(x-h)^{2}+ (y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle.

By direct comparison, it is evident that circle is centered at (-2,3).

True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).

4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).

5) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

6) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

5 0

3 years ago

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