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2 years ago

Help ASAP, i don't understand this.

Mathematics

1 answer:

Inessa [10]2 years ago

8 0

The given polynomial expressed as partial fraction is 5x^3 + 9/x

<h3>Polynomial function and partial fractions</h3>

Polynomial function are function that have a leading degree of 3. Given the expression below;

f(x) = (5x^4+9)/x

Applying partial fraction

Since the part fraction means separating the fraction into two parts, hence;

f(x) = 5x^4/x + 9/x

Simplify

Since there is value of x at both numerator and denominator, it will cancel out to have

f(x) = 5x^3 + 9/x

From the result, we can see that p(x) = 5x^3 and k = 9

Hence the given polynomial expressed as partial fraction is 5x^3 + 9/x

Learn more on polynomial here: brainly.com/question/2833285

#SPJ1

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A cottage has a gable roof. To the nearest foot, how wide is the cottage?A. 12 ftB. 24 ftC. 35 ftD. 70 ft

Sergio [31]

Answer: the answer is B: 24ft

Step-by-step explanation: To find how wide the triangle is identify your angles. You have a right angle which is equal to 90° and an angle that measures 46°. Add up both of these angles and you'll get 136°. A triangle can only have three angles that add up to 180. So subtract 180 and 136 you get 44. Multiply the hypotenuse by sin(46) to get the length of the side facing the opposite way of the angle that measures 44°. You will get 11.8 which is about 12. The other triangle is a congruent triangle meaning that it's angles and sides are the same. Add both 12's up and you have 24ft as your width for the cottage.

7 0

2 years ago

Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling

arlik [135]

a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

<h3>What is tension?</h3>

This is the opposing force in a stretched material.

<h3>a. Tension in the string</h3>

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

T = tension in sring and
W = weight of particle = mg where
m = mass of particle and
g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

<h3>b. Tension in chain</h3>

The expression for the tension in the chain is T = 2mg

<h3 />

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

T' = tension in chain and
T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

<h3 />

Learn more about tension here:

brainly.com/question/24994188

5 0

2 years ago

Solve for x<br>Please HELPPPPPPPPPPPPPPPPP ME ILL GIVE YOU BRAINLY

valina [46]

<h3>Answer:</h3>

x = 2

<h3>Explanation:</h3>

The rule for secants is that the product of segment lengths (on the same line) from the point of intersection to the points on the circle is a constant for any given point of intersection. Here, that means ...

... 3×(3+5) = 4×(4+x)

... 6 = 4+x . . . . divide by 4

... 2 = x . . . . . . subtract 4

_____

<em>Comment on this secant relationship</em>

Expressed in this way, the relationship is true whether the point of intersection is inside the circle or outside.

5 0

4 years ago

Read 2 more answers

From first principles, find the indicated derivatives

LenaWriter [7]

By definition of the derivative,

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)$

$\displaystyle\frac{dr}{ds} = \frac{3s^2}2$

6 0

3 years ago

What is the value of z in the equation 2(4z − 9 − 7) = 166 − 46?

kumpel [21]

Hi there!

2(4z - 9 - 7) = 166 - 46
let's make this a little more simpler...

2(4z - 16) = 120

use distributive property.
multiply 2 and 4z , 2 and -16.
8z - 32 = 120

add 32 on both sides to isolate the variable

8z = 152

divide both sides by 8...

z = 19

So your answer is A. 19

Hope this helped!! :)

8 0

3 years ago

Read 2 more answers