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2 years ago

Look at pic 10 pts will mark brainilest

Mathematics

1 answer:

Nina [5.8K]2 years ago

6 0

Answer:

For part one...

you will multiply 4.5 by 3 to get 13.5 .

For part two,

you will multiply 3m by 4 to get 12.

(: I hope this helps! BRAINLIEST is appreciated to get to virtuoso :)

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Question: What is the volume of the box? Explain how you found your solution.

Vikki [24]

The volume of the box is 100 cubic meter.

Step-by step explanation:

Given data:

Length of the box = 10 m

Width of the box = 5 m

Height of the box = 2 m

To find the volume of the box:

Volume of the box = length × width × height

= 10 m × 5 m × 2 m

= 100 cubic meter

Hence the volume of the box is 100 cubic meter.

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3 years ago

Sort each unit into the box indicating what it measures.

nadezda [96]

The sorting as been done below:

A unit of measurement is a quantity used as a standard to expressed a physical quantity.

Volume: Millimeter , Kiloliter

Length: Yard, Quart

Weight/Mass: Centigram, Ounce.

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brainly.com/question/13752528

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1 year ago

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary). 360, 353,346,... 360,353,346,...

Marysya12 [62]

Answer:

Step-by-step explanation:

the first answer is correct

3 0

1 year ago

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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

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2 years ago

Joan was asked to draw a right triangle how many right angles are in a right triangle

Temka [501]

Full Answer.
If the triangle is an equilateral triangle, then all three angles are exactly 60 degrees each. A right-angled triangle has one angle of 90 degrees, which is the right angle, with two more angles that total 90 degrees when added together.

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2 years ago

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