Diameter is the radius times 2, which is 18. 18 x 24 = 432 yards
Answer:
The parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.
Step-by-step explanation:
Given the parallelogram with sides 20 and 21 units with diagonal length 28 units.
we have to tell it is a rectangle or not.
The given parallelogram is rectangle if the angle at vertices are of 90° i.e the two triangle formed must be right angles i.e it must satisfy Pythagoras theorem
=
+
784=400+441=881
Not verified
∴ The sides of the parallelogram do not meet at right angles.
Hence, the parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.
Hope it helps
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Answer: Letter Choice, (B) ====> 4,256 pi cm^2
Step-by-step explanation:
<u>Formula: Surface Area of Cylinder = (2pi ) (r^2 ) + 2pi (r) (h)</u>
<u>Showing Work:</u>
<u>Radius of the Base ===> 28cm</u>
<u>Height =====> 48cm </u>
(2pi ) (r^2) + 2pi (28)(48)
2 (pi) (r^2) + (circumference) (height)
2( pi) (r^2 + 2)( pi)(r)(h)
2 pi * (2) (r^2 + (2)(r)(h)
2pi * (r^2 + rh)
2(r)(pi)(r + h)
2( 28)(pi)(28 + 48)
56(pi)(76)
4256(pi)^2
<u>Therefore, Your Answer ======> Letter Choice; (B) ======> 4,256pi cm^2</u>
Hope that helps!!!!! : )
<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
