Hey there!
4.50x + 5.50x - 7.50x
= 4.5x + 5.5x - 7.5x
= 10x - 7.5x
COMBINE the LIKE TERMS
= (10x - 7.5x)
= 10x - 7.5x
= 2.5x
≈ 2.50x
Therefore, your answer is: 2.50x
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
A= 15+z+ square root 17(z+15)/ z-2
z=2a^2/(a-1)^2 + 30a/(a-1)^2 - 15/(a-1)^2
Answer:
10.75
Step-by-step explanation:
The cost of an adult ticket is £6 more than that of a child ticket, so will be shown by c+6.
Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
so, a childs ticket is 4.75
now to find the cost of an adult ticket you add 6,
4.75 + 6
= 10.75
Answer:
Step-by-step explanation:
x+y=10
x=10-y
x=10-5
x=5
3y= -3x+30
3(10-y)= -3(10-y)+30
30-3y= -30+3y+30
30+30-30=6y
30=6y
y=5
Step-by-step explanation:
the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).
I think your teacher made a mistake, or you made one when typing the question in here.
there is no factor r that creates
15×r = 9
and
9×r = 5/27
it would mean that
15 × r² = 5/27
r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81
r = 1/9
but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9
and 9 × 1/9 = 9/9 = 1 is NOT 5/27
so, this can't be right.
on the other hand
15 × r = 9
r = 9/15 = 3/5
and then
9 × 3/5 = 27/5
so, either the sequence should have been
15, 5/3, 5/27
or (and I suspect this to be true)
15, 9, 27/5
under that assumption we have
s1 = 15
r = 3/5
sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)
s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =
= 3 × 19683/390625 = 59049/390625 =
= 0.15116544 ≈ 0.151
