the second duckling is wandering by 2.6 units distance than the first duckling .
<u>Step-by-step explanation:</u>
Here we have , Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) from the nest is (12,5) The second duckling's displacement is (13,-8) . We need to find How much farther did the second duckling wander than the first duckling. Let's find out:
Let a = (12,5) and b =(13,-8)
The distance each duckling wandered is the magnitude of its displacement vector. Therefore, the expression Distance second duck wandered is given by :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the second duckling is wandering by 2.6 units distance than the first duckling .
Answer:
x > 22
Step-by-step explanation:
<em>Hey there!</em>
Well to solve,
52 - 3x < -14
we need to single out x
52 - 3x < -14
-52 to both sides
-3x < -66
Divide both sides by -3
x > 22
The < changes to > because the variable number is a - being divided.
<em>Hope this helps :)</em>
Answer:
arc DB length = 14π feet
Step-by-step explanation:
Assuming point A is the center of the circle, arc DC has measure 180°. Arc DB has measure 40° less, so is 140°. Since you want this in terms of π, we need to convert the degree measure to radians. We do that by multiplying by (π/180) radians per degree:
arc DB = 140° = 140°(π/180°) radians
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Now that we know the arc measure in radians, we can find the length of the arc. It is given by the formula ...
s = rθ
where r represents the radius and θ is the measure of the arc in radians.
The arc length is ...
s = (18 ft)(7π/9) = 14π ft
Arc DB has a length of 14π feet.
I believe the Answer is a/22 ( that’s a fraction )
