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Natali5045456 [20]
3 years ago
6

Provided below are summary statistics for independent simple random samples from two populations. Preliminary data analyses indi

cate that the variable under consideration is normally distributed on each population. Decide whether use of the pooled​ t-test and pooled​ t-interval procedure is reasonable. x overbar 1equals461.8​, s 1equals46.4​, n 1equals9​, x overbar 2equals391.6​, s 2equals99.2​, n 2equals20 Is use of the pooled​ t-test and pooled​ t-interval procedure reasonable or not​ reasonable? Reasonable
Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

Explained

Step-by-step explanation:

Not reasonable, because it is not given or mentioned in the question that population standard deviation are equal. Although, use of the pooled t-test and pooled t-interval procedure is reasonable because the population follows normal distribution.

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A traditional, physical bank with online options is a type of online bank.
Dafna1 [17]

Answer:

True

Step-by-step explanation:

It is still a traditional bank. The online option is there for your convenience, but doesn't make the bank all online. Hope this helped!

6 0
2 years ago
Write the expression using rational exponents. Then simplify and convert back to radical notation.
ioda

Answer:

The radical notation is 3x\sqrt[3]{y^2z}

Step-by-step explanation:

Given

\sqrt[3]{27 x^{3} y^{2} z}

Step 1 of 1

Write the expression using rational exponents.

\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}

=a^{\frac{m}{n}}:\left({27 x^{3} y^{2} z})^{\frac{1}{3}}

$(a \cdot b)^{r}=a^{r} \cdot b^{r}:(27)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

=$(3^3)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

$=\left(3\right)\left(x}\right)} \cdot\left(y}\right)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

Simplify $3 x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3 x \sqrt[3]{y^{2} z}$

Learn more about radical notation, refer :

brainly.com/question/15678734

4 0
2 years ago
Which equation has the solution x=4?
ASHA 777 [7]
D.
Because 4 divided by 2 is 2
4 0
3 years ago
Read 2 more answers
If you are offered one slice from a round pizza (in other words, a sector of a circle) and the slice must have a perimeter of 24
VARVARA [1.3K]

Answer:

A 12 in diameter will reward you with the largest slice of pizza.

Step-by-step explanation:

Let r be the radius and \theta be the angle of a circle.

According with the graph, the area of the sector is given by

A=\frac{1}{2}r^2\theta

The arc lenght of a circle with radius r and angle \theta is r \theta

The perimeter of the pizza slice is composed of two straight pieces, each of length r inches, and an arc of the circle which you know has length s = rθ inches. Thus the perimeter has length

2r+r\theta=24 \:in

We need to express the area as a function of one variable, to do this we use the above equation and we solve for \theta

2r+r\theta=24\\r\theta=24-2r\\\theta=\frac{24-2r}{r}

Next, we substitute this equation into the area equation

A=\frac{1}{2}r^2(\frac{24-2r}{r})\\A=\frac{1}{2}r(24-2r)\\A=12r-r^2

The domain of the area is

0

To find the diameter of pizza that will reward you with the largest slice you need to find the derivative of the area and set it equal to zero to find the critical points.

\frac{d}{dr} A=\frac{d}{dr}(12r-r^2)\\A'(r)=\frac{d}{dr}(12r)-\frac{d}{dr}(r^2)\\A'(r)=12-2r

12-2r=0\\-2r=-12\\\frac{-2r}{-2}=\frac{-12}{-2}\\r=6

To check if r=6 is a maximum we use the Second Derivative test

if f'(c)=0 and f''(c), then f(x) has a local maximum at x = c.

The second derivative is

\frac{d}{dr} A'(r)=\frac{d}{dr} (12-2r)\\A''(r)=-2

Because A''(r)=-2 the largest slice is when r = 6 in.

The diameter of the pizza is given by

D=2r=2\cdot 6=12 \:in

A 12 in diameter will reward you with the largest slice of pizza.

3 0
3 years ago
Solve for x. Round to the nearest tenth, if necessary.
DENIUS [597]

Answer:

x=3.5 cm

Step-by-step explanation:

90/2 = 45 degrees

Soh Cah Toa

We have opposite and hypotenuse making sin.

Length×Sin(Angle)

5×Sin(45) = 3.53553cm

Rounded the the nearest tenth makes 3.5cm

6 0
3 years ago
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