Splitting up [0, 3] into 
equally-spaced subintervals of length 
gives the partition
![\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%20%5Cdfrac3n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac3n%2C%20%5Cdfrac6n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac6n%2C%20%5Cdfrac9n%5Cright%5D%20%5Ccup%20%5Ccdots%20%5Ccup%20%5Cleft%5B%5Cdfrac%7B3%28n-1%29%7Dn%2C%203%5Cright%5D)
where the right endpoint of the 
-th subinterval is given by the sequence
for 
.
Then the definite integral is given by the infinite Riemann sum
Answer:
there is one real solution
Step-by-step explanation:
use the quadratic formula. what is in the square root is called the discriminant.
since it came out to 0 there is one real solution
For the answer to the question above, <span>
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>
Answer:the cost for 40 children to attend along with 5 adult tickets = $ 417.55
Step-by-step explanation:
It costs 135.25 for 15 child tickets to the museum. Let us determine the cost per child ticket to the museum.
cost per child ticket to the museum.
= total cost of 15 child tickets / number of child tickets.
= 132.25 / 15 = 8.82
Adult tickets cost 12.95 each.
The cost of 40 child tickets is
40 × 8.82 = $352.8
The cost of 5 adult tickets = 5 × 12.95
=$ 64.75
the cost for 40 children to attend along with 5 adult tickets would be
352.8 + 64.75 = $ 417.55
Answer:
Step-by-step explanation:
