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qaws [65]
3 years ago
7

Which statement must be true

Mathematics
1 answer:
monitta3 years ago
4 0

Answer:

(C)

Step-by-step explanation:

AD and BC are parallel to each other. They are the same distance but they never touch.  

Your best answer would be C.

Brainilest appreciated.

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Sergeeva-Olga [200]
They are to make variables.

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3 years ago
ACDF is a trapezoid and
Sholpan [36]

Answer:

x = 7

Step-by-step explanation:

See the attached figure.

As shown: A C D F is a trapezoid and BE is a mid-segment.

The mid-segment of the trapezoid is the average of its bases.

BE = 0.5 ( A F + C D)

Given: CD = 18 , BE = 2x + 10   and   A F = 6x - 12

So,

2x + 10 = 0.5 ( 18 + 6x - 12)

Solve for x

2x + 10 = 0.5 (6 + 6x)

2x + 10 = 3 + 3x

10 - 3 = 3x - 2x

∴ x = 7

<u>So, the value of x is 7</u>

8 0
3 years ago
#19 <br> Quadrilateral ABCD is a parallelogram. What is the measure of
Burka [1]

Answer:

133°

Step-by-step explanation:

In the attached file

7 0
3 years ago
If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will
aleksandrvk [35]

Answer:

P(T\ n\ S) = \frac{1}{14}

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

Determine the probability of triangle being first then square being second

Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

P(T) = \frac{5}{15}

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

P(S) = \frac{n(S)}{Total}

P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

3 0
2 years ago
Determine if the triangles, ΔSXC and ΔDXY, are similar. If so, identify the similarity criterion.
Lesechka [4]
THE ANSWER IS B SAS SIMILARITY
3 0
3 years ago
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