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sergey [27]
4 years ago
7

Rectangle jklm is translated 3units to the left and 4 units up which rule represents the translation applied to rectangle JKLM t

o make J'K'L'M?
F:(x,y) --> (3x,4y)
G:(x,y)--> (x - 3,y+4)
H:(x,y) --> (3x - 4y)
J:(x,y) --> (x+3,y- 4)
Mathematics
1 answer:
lapo4ka [179]4 years ago
4 0

Answer:

G

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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Step-by-step explanation:

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The graph of a polynomial function of degree 5 has three x-intercepts, all with multiplicity 1. Describe the nature and number o
mr Goodwill [35]

For this case suppose that we have a polynomial in its standard form of the form:

f (x) = ax ^ 5 + bx ^ 4 + cx ^ 3 + dx ^ 2 + ex + f

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6 0
3 years ago
Read 2 more answers
Quick algebra 1 question for 10 points!
jonny [76]

Answer:

\displaystyle{f(x) = -2(x-3)^2 + 2}

Step-by-step explanation:

To find y-intercept of a graph, we have to substitute x = 0 to find it - consider each functions:

<u>First Choice</u>

\displaystyle{f(x) = 2x(x+14)-64}\\\\\displaystyle{f(0) = 2\cdot 0(0+14)-64}\\\\\displaystyle{f(0) = 0\cdot 14-64}\\\\\displaystyle{f(0) = -64}

<u>Second Choice</u>

<u />\displaystyle{f(x) = (x+4)^2+2x}\\\\\displaystyle{f(0) = (0+4)^2 + 2(0)}\\\\\displaystyle{f(0) = 4^2}\\\\\displaystyle{f(0) = 16}

<u>Third Choice</u>

<u />\displaystyle{f(x) = (x-16)^2 + 4}\\\\\displaystyle{f(0) = (0-16)^2 + 4}\\\\\displaystyle{f(0) = (-16)^2 + 4}\\\\\displaystyle{f(0) = 256 + 4}\\\\\displaystyle{f(0) = 260}

<u>Fourth Choice</u>

<u />\displaystyle{f(x) = -2(x-3)^2 + 2}\\\\\displaystyle{f(0) = -2(0-3)^2 + 2}\\\\\displaystyle{f(0) = -2(-3)^2 + 2}\\\\\displaystyle{f(0) = -2\cdot 9 + 2}\\\\\displaystyle{f(0) = -18+2}\\\\\displaystyle{f(0) = -16}\\

Therefore, fourth choice is correct.

6 0
2 years ago
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