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4 years ago

How do you answer this

Mathematics

1 answer:

Fynjy0 [20]4 years ago

8 0

$\bf 2\left(\frac{1}{2} \right)+3+\cfrac{1}{7}\implies \cfrac{2}{2}+3+\cfrac{1}{7}\implies 1+3+\cfrac{1}{7}\impliedby \textit{LCD of 7}
\\\\\\
\cfrac{7\cdot 1j+7\cdot 3+1\cdot 1}{7}\implies \cfrac{7+21+1}{7}\implies \cfrac{29}{7}\implies 4\frac{1}{7}$

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omeli [17]

Answer:

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Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Find the distance between (-6,4) and (-2,1)

zhannawk [14.2K]

Answer:

$d=2.65$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2-(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the formula to find distance d:

$d=\sqrt{(-2-(-6))^2-(1-4)^2}$

$d=\sqrt{(-2+6))^2-(-3)^2}$

$d=\sqrt{(4)^2-9}$

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3 years ago

Which expression below has the LEAST value?

Alexandra [31]

Answer: A

Step-by-step explanation:
Your answer is A.

Value of 3.78 x 10=37.8

Value of 5.99 x 102=699.98

value of 7.35 x 10-12=61.5

Value of 9.46 x 10-10=84.6.

Least value to greatest value

3.78 x 10=37.8 Least value

7.35 x 10 - 12=61.5 Sencond least value

9.46 x 10 - 10=84.6 Sencond greatest value

5.99 x 102=699.98 Greatest value

Hope it helps have a great day:)

7 0

2 years ago

Divide 9 by w, then subtract v from the result

Bas_tet [7]

Answer:

9/w=x(your result)

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Please mark my answer as brainliest

Step-by-step explanation:

8 0

3 years ago

The dimensions of a rectangular garden were 4m by 5m. Each dimension was increased by the same amount the garden then had an are

pogonyaev

The dimension of new garden is 7 meter by 8 meter

Solution:

The dimensions of a rectangular garden were 4m by 5m

Length = 4 m

Width = 5 m

Each dimension was increased by the same amount the garden then had an area of 56 square meter

Let "x" be the amount of increase

Then,

Length = 4 + x

Width = 5 + x

Also, given that,

New area = 56 square meter

The area of rectangle is given as:

$Area = length \times width$

Substituting the values we get,

$56 = (4+x)(5+x)\\\\56 = 20 + 4x + 5x + x^2\\\\x^2 + 9x + 20 - 56 = 0\\\\x^2 + 9x -36=0$

Let us solve the above equation by quadratic formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{For } x^2+9x-36 \text{ we get , }$

a = 1 and b = 9 and c = -36

Substituting the values of a = 1 ; b = 9 ; c = -36 in above quadratic formula we get,

$x = \frac{-9\pm \sqrt{9^2-4\cdot \:1\left(-36\right)}}{2\cdot \:1}\\\\x = \frac{-9\pm \sqrt{81+144}}{2}\\\\x = \frac{-9 \pm 15}{2}$

We get two solutions,

$x = \frac{-9+15}{2} \text{ or } x = \frac{-9-15}{2}\\\\x = 3 \text{ or } x = -12$

Since dimension cannot be negative, ignore x = -12

Thus solution is x = 3

Length = 4 + x = 4 + 3 = 7

Width = 5 + x = 5 + 3 = 8

Thus dimension of new garden is 7 meter by 8 meter

5 0

3 years ago