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Monica [59]
3 years ago
13

Help ASAP math homework

Mathematics
2 answers:
astraxan [27]3 years ago
5 0
\left\{\begin{array}{ccc}y \ \textgreater \  -x-3\\y\leq4x+2\end{array}\right\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0;-3)\\for\ x=-3\to y=-(-3)-3=3-3-=0\to(-3;0)\\\\y=4x+2\\for\ x=0\to y=4(0)+2=0+2=2\to(0;2)\\for\ x=-1\to y=4(-1)+2=-4+2=-2\to(-1;-2)\\\\Answer\ in\ attachment

poizon [28]3 years ago
4 0
See attachment for graph.

Notes: graph each line as if they are "equal".
Then draw the lines as:
dashed for < and > 
solid for ≤ and ≥
Next, choose a test point and plug it into both equations.  If the result is True for BOTH equations, then shade that section.

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Read 2 more answers
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
2 years ago
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