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jeyben [28]
3 years ago
12

What is the probability the computer produces the first letter of your first name

Mathematics
1 answer:
inysia [295]3 years ago
4 0

Answer:

1 out of 26

Step-by-step explanation:

Because there are 26 letters in the alphabet !

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9. Find the lowest common denominator for the following pairs of fractions.
andreev551 [17]
A. 12
B.8
C.8
D.16

Hope this helps
6 0
3 years ago
The graphs of y= ‐4x and y= ‐4x+2 are shown. Use the drop-down menus to complete the statements.
VARVARA [1.3K]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the value of b that makes the lines, given by 3x-y=4 and 2y+4bx=1, perpendicular?
USPshnik [31]

b = 1/6

Explanation:

3x-y=4 ...1st equation

Rewriting in slope- intercept form:

y = 3x - 4

2y+4bx=1

Rewriting in slope- intercept form:

2y = -4bx + 1

y = -4bx/2 + 1/2

Equation of line: y = mx + c

where m = slope, c = intercept

For a line to be perpendicular to another, the slope of one will be the negative reciprocal of the slope of another.

Slope of the 1st equation = 3

m = 3

reciprocal of 3 = 1/3

negative reciprocal of 3 = -1/3

Slope of the 2nd equation = -4b/2

we equate both slope:

negative reciprocal of 3 = -4b/2

-1/3 = -4b/2

cross multiply:

-1(2) = 3(-4b)

-2 = -12b

Divide both sides by -12:

-2/-12 = -12b/-12

b = 1/6

Hence, the value of b that makes the lines perpendicular is 1/6

6 0
1 year ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
Read 2 more answers
Help i always mark brainliest to whoever answers first
belka [17]

Answer:

<em>(0, 2)</em>

Step-by-step explanation:

Function is the relation where each value of "x" has single value of "y"

The table contains pair (0, - 2) if table would include (0, 2) the relation in table would be not a function.

8 0
3 years ago
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