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3 years ago

Which of the following points would be on the graph of the equation y= -4x+6

Mathematics

2 answers:

Alex777 [14]3 years ago

6 0

Answer:

B: (-4, 22)

Step-by-step explanation:

for these types of problems, you just need to plug in the values

A: y= -4(-4) + 6 = 22 — NOT 10

B: y= -4(-4) + 6 = 22 — CORRECT

C: y= -4(1) + 6 = 2 — NOT 10

D: y= -4(1) + 6 = 2 — NOT -2

Advocard [28]3 years ago

6 0

Answer:

Step-by-step explanation:

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What is the value of the expression<br> Зр divided by8 + 4 when p is 32?

Otrada [13]

Answer:

-4

Step-by-step explanation:

Divide each side by '-1'.

p = -4

Simplifying

p = -4

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3 years ago

A 3-gallon bucket of paint costs $103.68. What is the price per cup?

prohojiy [21]

Answer:34.56

Step-by-step explanat 103.68 divded by 3 = 34.56

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3 years ago

About 12% of individuals write with their left hands. If a class of 130 students meets in a classroom with 130 individual desks,

Lynna [10]

Answer:

0.1019

Step-by-step explanation:

Probability, p=12%=0.12

Sample size, n=130 students

Those writing with left=14 students

Using the formula for binomial distribution

P(X≤x)= $\left[\begin{array}{}n\\x\end{array}\right]p^{x}(1-p)^{n-x}$

Substituting 0.12 for p, 130 for n, 14 for x we obtain

P(X≤x)= $\left[\begin{array}{}130\\14\end{array}\right]0.12^{14}(1-0.12)^{130-14}$

P(X≤x)= $130C14*0.12^{14}(0.88)^{116}$

P(X≤x)=0.1019

3 0

3 years ago

What is 2/3+4/5 simplified ?

11Alexandr11 [23.1K]

Answer:

$\frac{2}{3} + \frac{4}{5}$

$= \frac{10 + 12}{15}$

$= \frac{22}{15}$

$= 1 \frac{7}{15}$

6 0

3 years ago

Read 2 more answers

Could someone help me, please?

k0ka [10]

We can rewrite the expression under the radical as

$\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4$

then taking the fourth root, we get

$\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|$

Why the absolute value? It's for the same reason that

$\sqrt{x^2}=|x|$

since both $(-x)^2$ and $x^2$ return the same number $x^2$ , and $|x|$ captures both possibilities. From here, we have

The absolute values disappear on all but the $b$ term because all of $\dfrac32$ , $a^2$ and $c^4$ are positive, while $b^3$ could potentially be negative. So we end up with

$\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4$

3 0

3 years ago