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ASHA 777 [7]
3 years ago
9

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Computers and Technology
1 answer:
V125BC [204]3 years ago
6 0
Skakskdnsmakakkskzskskslslskakidfjjfueiskxncjowkcnjsosldnxnxisoszmsmzkakaskzkkz 浜はまはまはたはまりまる
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click attachment to see correct answer. Which agencies run the Landsat Program? The Landsat program is run by ___ and ___.​
Ksju [112]

Answer:

ancient times were nicr

Explanation:

5 0
2 years ago
Identify 5 internal and external hardware components of a server
UNO [17]

Answer:

Internal:

#CPU; That retrieves &execute instructions.

#Modem; Modulates& demodulates electric signals.

#RAM;Gives application a place to store &access data on a short time periods.

External:

#Mouse; Transmits commands and controlling movements.

#Moniter; Device used to display video output from computer.

#Printer; Accepts text, graphics to the paper.

Explanation:

Hope this will help you.

5 0
3 years ago
Hat is the limit of virtual machines that can be connected to a virtual network?
skad [1K]

<u>Unlimited </u> of virtual machines that can be connected to a virtual network.

<h3>What is a virtual machine employed for?</h3>

Virtual machines (VMs) allow a business to run an operating system that conducts like a thoroughly separate computer in an app window on a desktop.

<h3>What is a virtual machine in simple words?</h3>

A virtual machine (VM) is a virtual domain that functions as a virtual computer system with its CPU, memory, network interface, and storage, constructed on a physical hardware system (located off- or on-premises)

To learn more about Virtual machines , refer

brainly.com/question/26771683

#SPJ4

4 0
1 year ago
Evaluating sorts given the following array: 41, 32, 5, 8, 7, 50, 11 show what the array looks like after the first swap of a bub
irga5000 [103]

The way that  the array will looks like after the first swap of a bubble sort in ascending order is   {5,32,41, 8,7,50,11}.

<h3>Who do you Write sort code in JAVA?</h3>

It will be:

class SSort

{

  void sort(int array[])

  {

      int n = array.length;

      for (int i = 0; i < 2; i++)

      {

          int minimum_index = i;

          for (int j = i+1; j < n; j++)

              if (array[j] < array[minimum_index])

                  minimum_index = j;

           int temp = array[minimum_index];

          array[minimum_index] = array[i];

          array[i] = temp;

      }

  }

   void printArray(int array[])

  {

      int n = array.length;

      for (int i=0; i<n; ++i)

          System.out.print(array[i]+" ");

      System.out.println();

  }

  public static void main(String args[])

  {

      SSort s = new SSort();

      int array[] = {41, 32, 5, 8, 7, 50, 11};

      s.sort(array);

      System.out.println("After first two iteration of Selection sort:");

      s.printArray(array);

  }

}

Therefore, The way that  the array will looks like after the first swap of a bubble sort in ascending order is   {5,32,41, 8,7,50,11}.

Learn more about array  from

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8 0
2 years ago
Write a program in Java programming language that given two clock times prints out the absolute number of minutes between them
Triss [41]

Answer:

// Java Program to Find the difference

// between Two Time Periods

// Importing the Date Class from the util package

import java.util.*;

// Importing the SimpleDateFormat

// Class from the text package

import java.text.*;

public class GFG {

public static void main(String[] args) throws Exception

{

 // Dates to be parsed

 String time1 = "18:00:00";

 String time2 = "7:30:50";

 // Creating a SimpleDateFormat object

 // to parse time in the format HH:MM:SS

 SimpleDateFormat simpleDateFormat

  = new SimpleDateFormat("HH:mm:ss");

 // Parsing the Time Period

 Date date1 = simpleDateFormat.parse(time1);

 Date date2 = simpleDateFormat.parse(time2);

 // Calculating the difference in milliseconds

 long differenceInMilliSeconds

  = Math.abs(date2.getTime() - date1.getTime());

 // Calculating the difference in Hours

 long differenceInHours

  = (differenceInMilliSeconds / (60 * 60 * 1000))

  % 24;

 // Calculating the difference in Minutes

 long differenceInMinutes

  = (differenceInMilliSeconds / (60 * 1000)) % 60;

 // Calculating the difference in Seconds

 long differenceInSeconds

  = (differenceInMilliSeconds / 1000) % 60;

 // Printing the answer

 System.out.println(

  "Difference is " + differenceInHours + " hours "

  + differenceInMinutes + " minutes "

  + differenceInSeconds + " Seconds. ");

}

}

7 0
2 years ago
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