Answer:
Lots of "ifs" here.
A=bh/2 is the formula for the area of a triangle.
A=bh is the formula for the area of a rectangle or a parallelogram.
If the 6 & 4 area the base & height of a rectangle, then (6)(4) = 24 in^2
If the 6 & 10 are the base and height of a triangle, then 1/2(6)(10) = 30 in^2
Step-by-step explanation:
Answer:
(10, 14)
Step-by-step explanation:
To solve this system let's use substitution:
Solve the first equation for x, obtaining x = 24 - y, and then substitute 24 - y for x in the second equation:
3(24 - y) + 5y = 100
Performing the indicated multiplication, we get:
72 - 3y + 5y = 100
Combining like terms results in 72 - 100 = -2y, or -28 = -2y
Thus, y must be 14.
If y = 14, then the first equation tells us that x = 10.
Check: Is this true? 3(10) + 5(14) = 100 YES
The solution is (10, 14).
What was it about the questions on the best that you were supposed to compare to this solution?
Hello there.
<span>Which line is a graph of the equation 2x + 5y = 10?
Coordinate plane with the following lines graphed: Line A contains a slope of five-halves and y-intercept of 2; Line B contains a slope of negative five-halves and y-intercept of 2; Line C contains a slope of five-halves and y-intercept of negative 2; and Line D contains a slope of negative five-halves and y-intercept of negative 2.
</span><span>line b</span>
Given
- f(n) values for n=1,2,3,4
- possible candidates for the function
Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.
N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]
N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]
Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]
Solution: f(n)=4(3^(n-1))
