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Vladimir79 [104]
3 years ago
6

How can brady use fraction strips to show that 3/4 and 7/8 are not equipment

Mathematics
1 answer:
Mila [183]3 years ago
5 0

Answer:

He can use two figures to demonstrate that they are not equal

Step-by-step explanation:

I will upload a picture

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A line goes through the point (2, 4) and has a slope of 3/2. Which of the following points is also on the line? CHOOSE ALL THAT
Korolek [52]
Hmmmm not sure

Explanation: I took this test and got it correct
8 0
3 years ago
Write the unit fraction depicted in the model as a percent.<br><br> One-fourth
yan [13]

Answer:

As

1/4×100 = 0.25×100

            = 25%

Thus,

1/4 = 25%

Step-by-step explanation:

Given the fraction

1/4

  • In order to write the fraction 1/4 as a percent, all we need is to multiply 1/4 by 100.

i.e.

1/4×100 = 0.25×100

            = 25%

Therefore, we conclude that:

1/4 = 25%

4 0
2 years ago
There are 1560 students enrolled at greenwood middle school if 85% of these ride the bus how many does not ride the bus
loris [4]

Answer: 1326 students won't come to school

Step-by-step explanation:

All you have to do is find out 85% of 1560 which is 1326 students!

4 0
3 years ago
A set of data already has the values 11, 14, 23, and 16. What value would have to be added to the set for the mean of the five n
KonstantinChe [14]
1) Take 18 and multiply it by 5 = 90
2) Then subtract 26 = 64
3) Then subtract 18 = 46
4) Then subtract 12 = 34
5)  Then subtract 8 = 26
 
The answer is 26.

5 0
3 years ago
Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

 ( \frac{x^{2}-2xy+y^{2}}{2})-(\frac{x^{2}+2xy+y^{2}}{2})-16=0

* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
3 years ago
Read 2 more answers
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